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3 years ago

9

Enter the values for the highlighted variables to

1 answer:

kotegsom [21]3 years ago

8 0

Answer:

a= -1

b=-9

c=9

d=3

e=3

f=2

g=1.5

Step-by-step explanation:

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I need number 2 and 3

Vilka [71]

Answer:

Its 2 and only 2 press 2 its true press 2 please

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4 years ago

10 is 5% of what number

Tcecarenko [31]

The number is 200 .
10 is 5% of 200

8 0

3 years ago

A car traveling at a constant speed travels 1000 ft in 12 seconds. how long in hours will it take to travel 175 miles?

artcher [175]

9514 1404 393

Answer:

3.08 hours

Step-by-step explanation:

We assume you're interested in the time in hours.

$175\text{ mi}\times\dfrac{12\text{ s}}{1000\text{ ft}}\times\dfrac{5280\text{ ft}}{1\text{ mi}}\times\dfrac{1\text{ h}}{3600\text{ s}}=\dfrac{175\times12\times5280}{1000\times3600}\text{ h}=\boxed{3.08\text{ h}}$

It will take 3.08 hours to travel 175 miles at that speed.

7 0

3 years ago

Find the degree measures of the next two positive and the previous two negative angles that are coterminal with the angle 75°.

AlladinOne [14]

9514 1404 393

Answer:

435°, 795°
-285°, -645°

Step-by-step explanation:

Add or subtract multiples of 360° to find coterminal angles.

<u>Positive</u>

75° +360° = 435°

75° +2×360° = 795°

<u>Negative</u>

75° -360° = -285°

75° -2×360° = -645°

5 0

3 years ago

A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u

Kryger [21]

Given: $f(x) = \frac{1}{x-2}$

$g(x) = \frac{2x+1}{x}$

A.)Consider

$f(g(x))= f(\frac{2x+1}{x} )$

$f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}$

$f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}$

$f(\frac{2x+1}{x} )=\frac{x}{1}$

$f(\frac{2x+1}{x} )=1$

Also,

$g(f(x))= g(\frac{1}{x-2} )$

$g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}$

$g(\frac{1}{x-2} )= \frac{x }{1}$

$g(\frac{1}{x-2} )= x$

Since, $f(g(x))=g(f(x))=x$

Therefore, both functions are inverses of each other.

B.

For the Composition function $f(g(x)) = f(\frac{2x+1}{x} )=x$

Since, the function $f(g(x))$ is not defined for $x=0$ .

Therefore, the domain is $(-\infty,0)\cup(0,\infty)$

For the Composition function $g(f(x)) =g(\frac{1}{x-2} )=x$

Since, the function $g(f(x))$ is not defined for $x=2$ .

Therefore, the domain is $(-\infty,2)\cup(2,\infty)$

8 0

4 years ago