Answer:
The P-value is 0.0234.
Step-by-step explanation:
We are given that a statistics practitioner calculated the mean and the standard deviation from a sample of 400. They are x = 98 and s = 20.
Let = population mean.
So, Null Hypothesis, : = 100 {means that the population mean is equal to 100}
Alternate Hypothesis, : > 100 {means that the population mean is more than 100}
The test statistics that will be used here is One-sample t-test statistics because we're yet to know about the population standard deviation;
T.S. = ~
where, = sample mean = 98
s = sample standard deviation = 20
n = sample size = 400
So, the test statistics = ~
= -2
The value of t-test statistics is -2.
Now, the P-value of the test statistics is given by;
P( < -2) = 0.0234 {using the t-table}
It would be -8d + 3w because
-(8d -3w)
you would be multiplying the hole equation by -1
so 8d would become -8d
and -3w would become positive +3w meaning the answer is -8d +3w
Answer:
1. x1=15.75.
2. 24/48=0.5
3. 24/25=0.96
Step-by-step explanation:
1. 15.75/18=0.875
2. you multiply 48 times 0.5 to find 24.
3. multiply 0.96 with 25 to get 24.
100 notes were altogether
<em><u>Solution:</u></em>
Given that ratio of the number of $2 notes to the number of $5 notes was 4 : 1
number of $2 notes : number of $5 notes = 4 : 1
Let 4x be the number of $ 2 notes
Let 1x be the number of $ 5 notes
Given that total value of notes is $ 260
Therefore,
$ 2 (number of $ 2 notes ) + $ 5(number of $ 5 notes ) = $ 260
$ 2(4x) + $ 5(1x) = $ 260
8x + 5x = 260
13x = 260
x = 20
<em><u>Thus number of notes altogether is given as:</u></em>
4x + 1x = 4(20) + 1(20) = 80 + 20 = 100
Thus 100 notes were altogether
