All categories

3 years ago

1. The linear equation y = 1/4x tells us that this line is going to be more vertical or horizontal? Explain.

1 answer:

5 0

Its going more horizontal because the slope has you go up 1 and right 4, meaning you are going right more than you are going up

You might be interested in

Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b

trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

$6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right]$ ÷ $2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]$

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) $\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}$

( 2 ) $\sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}$

These two identities makes sin(π / 10) = $\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}$ , and cos(π / 10) = $\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}$ .

Therefore cos(2π / 5) = $\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}$ , and sin(2π / 5) = $\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}$ . Substitute,

$6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right]$ ÷ $2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]$

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

$6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right]$ ÷ $2\sqrt{2}\left[0-i\right]$

And now simplify this expression to receive our answer,

$6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right]$ ÷ $2\sqrt{2}\left[0-i\right]$ = $-\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i$ ,

$-\frac{3\sqrt{5+\sqrt{5}}}{4}$ = $-2.01749\dots$ and $\:\frac{3\sqrt{3-\sqrt{5}}}{4}$ = $0.65552\dots$

= $-2.01749+0.65552i$

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = $\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}$ , sin(2π / 5) = $\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}$ , cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

$6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}$

We know that $6\sqrt{5+\sqrt{5}} = 16.13996\dots$ and $-\:6\sqrt{3-\sqrt{5}} = -5.24419\dots$ . Therefore,

Solution : $16.13996 - 5.24419i$

Which rounds to about option b.

7 0

3 years ago

A music store has 500 guitar picks. They order 15 boxes with 9 picks each. They sell 19 boxes that have 10 picks each. The store

weqwewe [10]

Answer:

yes

Step-by-step explanation:

6 0

3 years ago

How do I check 102÷17=6 without multiplying

insens350 [35]

You could add 6 togetber 17 times? Sorry for the stupid answer I couldn't think of anything else I searched it up and I couldn't find anything at all

3 0

3 years ago

Please, help thanks! I would like an explanation how to do it too, IF you dont mind.

Aneli [31]

Answer:

Phoebe has £180, Andy has £60, and Polly has £30.

Step-by-step explanation:

Ok, to start of let's establish some variables! We'll give Phoebe the variable "p", Andy the variable "a", and Polly the variable "o". By giving each person a variable we can create an equation and solve for it!

So, what do we know?

Well we know the following information...

p + a + o = 270

(Phoebe + Andy + Polly = £270)

p = 3a

(Phoebe = 3 times more than Andy)

a = 2o

(Andy = 2 times more than Polly)

To be able to solve this equation we have to solve for just one variable first.The only one we can use is "o" for Polly!

3(2o) + 2o + o = 270

6o + 2o + o = 270 (Distribute 3 to get like terms)

9o = 270 (Combine like terms [6+2+1])

o = 30 (Divide by 9 on both sides to get "o" by itself)

Now that we have how much Polly has, we have to solve for Andy and Phoebe. (To do this we will input our value, 30, where our variable is "o")

Andy

a = 2(30) (Input term)

a = 60 (Multiply by 2 to get final answer)

(Since we now know what Andy has we can input 60 into our "a" variable to solve for Phoebe)

Phoebe

p = 3(60) (Input term)

p = 180 (Multiply by 3 to get final answer)

Now! Just to check we are going to input our variables into our original equation to be sure we have the right variables.

p + a + o = 270

180 + 60 + 30 = 270!!

Hope this Helps! :)

Have any questions? Ask below in the comments and I will try my best to answer.

-SGO

4 0

2 years ago

The average number of stars in a galaxy is about 5x10^11 and the total number of galaxies is about 5.2x10^9. what is the total n

Arisa [49]

Answer:

2.6 x 10^21

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10 If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

4 0

3 years ago