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Vsevolod [243]
3 years ago
6

ohn is interested in purchasing a multi-office building containing five offices. The current owner provides the following probab

ility distribution indicating the probability that the given number of offices will be leased each year. Number of Lease Offices012345 Probability5/323/163/321/49/321/32 If each yearly lease is $12,000, how much could John expect to collect in yearly leases for the whole building in a given year
Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0

Answer:

$28,875

Step-by-step explanation:

The given table is:

\left|\begin{array}{c|cccccc}$Number of Lease Offices&0&1&2&3&4&5\\$Probability&5/32&3/16&3/32&1/4&9/32&1/32\end{array}\right|

The expected probability is derived using the formula: \sum_{i=0}^{5}x_iP(x_i)

Therefore, for the given distribution,

Expected Probability

=(0*\frac{5}{32})+ (1*\frac{3}{16})+ (2*\frac{3}{32})+ (3*\frac{1}{4})+ (4*\frac{9}{32})+ (5*\frac{1}{32})\\=2.40625

If each yearly lease is $12,000

The Expected Yearly Lease for the Whole Building=2.40625 X 12000

=$28,875

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2 years ago
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Which of the following choices shows the proper use of the distributive property?
lianna [129]

Answer:

-2(6x - y)  = -12x +2y

Step-by-step explanation:

Required

Which shows distributive property

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a(b + c) = a * b + a * c

So, the solution to -2(6x - y) is:

-2(6x - y)

Open bracket

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6 0
3 years ago
Using a 52 card deck, how many 5 card hands have either 5 hearts or 4 hearts and 1 club
777dan777 [17]

Answer:

10,582

Step-by-step explanation:

We can choose 5 cards from 52 card deck in

      n = \binom{52}{5} = \frac{52!}{5!(52-5)!}  = \frac{52!}{5!47!} = \frac{\cancel{47!} \cdot 48 \cdot 49 \cdot 50 \cdot 51 }{5! \cancel{47!}} = \frac{ 48 \cdot 49 \cdot 50 \cdot 51 }{1 \cdot 2 \cdot 3 \cdot 4 \cdot 5}  = 2 \; 598 \; 960

ways.

Now, let's calculate the number of ways we can choose 5 hearts. We know that in a 52 card deck, we have 13 hearts. Therefore, the number of ways to choose 5 hearts is

       n_1 = \binom{13}{5} = \frac{13!}{5!(13-5)!} =  \frac{13!}{5!8!} = \frac{8! \cdot 9 \cdot 10 \cdot 11 \cdot 12 \cdot 13}{5!8!} = \frac{9 \cdot 10 \cdot 11 \cdot 12 \cdot 13}{1 \cdot 2 \cdot 3 \cdot 4 \cdot 5} = 1287

Similarly, number of ways to choose 4 hearts equals \binom{13}{4} and number of ways to choose 1 club equals \binom{13}{1}, since there are also 13 clubs in the deck.

Therefore, the number of ways of choosing 4 hearts and 1 club equals

                                   n_2 = \binom{13}{4} \cdot \binom{13}{1} = 9295

The probability of this event is calculated as

           P(A) = \frac{\text{total number of ways to choose 5 hearts or 4 hearts and a club}}{\text{total number of ways to choose 5 cards from a deck of 52 cards}}

Therefore

                     P(A) = \frac{n_1+n_2}{n} = \frac{1287+9295}{2598960} =0.0040716 \approx 0.0041

5 0
3 years ago
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