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Ne4ueva [31]
3 years ago
13

Really need help on #15 please.

Mathematics
1 answer:
ollegr [7]3 years ago
5 0

Step-by-step explanation:

Let's call L the length and W the width.  The length is 10 feet longer than the width, so:

L = W + 10

The area is the length times width, so:

119 = LW

Substituting:

119 = (W + 10) W

119 = W² + 10W

0 = W² + 10W − 119

0 = (W + 17) (W − 7)

W = -17 or 7

Since W must be positive, W = 7.

L = W + 10

L = 17

The length and width are 17 feet and 7 feet, respectively.

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5 0
3 years ago
Susan and Steven are cousins. The sum of their ages is 33. The difference between three times Steven's age and half of Susan's a
VARVARA [1.3K]
The complete question is
Susan and Steven are cousins. The sum of their ages is 33. The difference between three times Steven's age and half of Susan's age is 36. Find <span>the age of Susan and Steven

let
x-----> </span>Susan's age
y---->  Steven's age

we know that
y+x=33-----> equation 1
3y-x/2=36----> multiply by 2----> 6y-x=72----> equation 2
adds equation 1 and equation 2

y+x=33
6y-x=72
-------------+
7y=105--------> y=15
x=33-y----> x=33-15----> x=18

the answer is
Susan's age is 18
Steven's age is 15

5 0
3 years ago
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