Let's assume
length of Ribbon A is A
length of Ribbon B is B
length of Ribbon C is C
we are given
A=B+20% of B
A=1.2B
B=C-20% of C
B=0.80C
now, we can find relation between A and C
A=1.2B
we can plug B
A=1.2*0.80C
A=0.96C
so,
Ribbon A is 4 % shorter than Ribbon C.......Answer
<h3>
Answer:</h3>
- a_n = -3a_(n-1); a_1 = 2
- a_n = 2·(-3)^(n-1)
<h3>
Step-by-step explanation:</h3>
A) The problem statement tells you it is a geometric sequence, so you know each term is some multiple of the one before. The first terms of the sequence are given, so you know the first term. The common ratio (the multiplier of interest) is the ratio of the second term to the first (or any term to the one before), -6/2 = -3.
So, the recursive definition is ...
... a_1 = 2
... a_n = -3·a_(n-1)
B) The explicit formula is, in general, ...
... a_n = a_1 · r^(n -1)
where r is the common ratio and a_1 is the first term. Filling in the known values, this is ...
... a_n = 2·(-3)^(n-1)
<span>5a-25
= 5(a-5)
----------------------</span>
Let the amount of adult tickets sold be x
Since the total of 380 tickets sold consists of the amount of adult tickets and the amount of children tickets that are 70 fewer:
x + (x - 70) = 380
2x - 70 =380
2x = 450
x = 225
Therefore, the amount of adult tickets sold is 225
Answer:
The correct answer is the sales tax charged is $5.61 for $66 dinner at 8.5% tax rate.
Step-by-step explanation:
Cost of the dinner is $22. Tax levied on it is $1.87
Let x% is the rate of tax in the city.
Therefore, x% of 22 = 1.87
⇒ x = 1.87 × 
= 8.5
Therefore 8.5% is the tax rate in the city on foods.
Now another dinner costs $66.
Tax levied on it at the same percentage is given by 8.5% of 66 = $5.61.
Thus $5.61 as sales tax would be charged for a $66 dinner.
