(x-4)^2+12(x-4)+20=0
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Answer:
Least positive integer divisible by the numbers 2, 4, and 7 is 28
Step-by-step explanation:
We can find the least positive integer divisible by the numbers 2, 4, and 7 by taking the LCM
First lets List all prime factors for each number.
Prime Factorization of 2
2 is prime =>
Prime Factorization of 4 is:
2 x 2 =>
Prime Factorization of 7 is:
7 is prime =>
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 7
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 7 = 28