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Brilliant_brown [7]
3 years ago
9

When the shuttle bus comes to a sudden stop

Mathematics
2 answers:
PIT_PIT [208]3 years ago
8 0

Answer:

2.58 seconds

Step-by-step explanation:

Given: the shuttle bus comes to a sudden stop  to avoid hitting a dog, it decelerates uniformly  at 3.8 \text{m}/\text{s}^2 as it slows from 9.8 \text{m}/\text{s} to 0 \text{m}/\text{s}.

To Find: the time interval of acceleration for  the bus.

Solution:

Initial speed of shuttle bus \text{u}=9.8 \text{m}/\text{s}

Final speed of shuttle bus \text{v}=0 \text{m}/\text{s}

acceleration =3.8 \text{m}/\text{s}^2

using first equation of motion

\text{v}=\text{u}+\text{a}\text{t}

as speed decreases acceleration will be negative

\text{v}=\text{u}-\text{a}\text{t}

putting value in equation

0=9.8-3.8\text{t}

3.8\text{t}=9.8

\text{t}=\frac{9.8}{3.8}

\text{t}=2.58 \text{seconds}

It takes 2.58\text{s} to decelerate to  0 \text{m}/\text{s}

abruzzese [7]3 years ago
5 0
The question is asking to calculate the time interval of acceleration for the bus and base on my own calculation, I would say that the answer would be 2.58 seconds. I hope you are satisfied with my answer and feel free to ask for more. I hope you are satisfied with my answer and feel free to ask for more 
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