Question

When the shuttle bus comes to a sudden stop

Answer 1

Answer:

2.58 seconds

Step-by-step explanation:

Given: the shuttle bus comes to a sudden stop  to avoid hitting a dog, it decelerates uniformly  at $3.8$ $\text{m}/\text{s}^2$ as it slows from $9.8$ $\text{m}/\text{s}$ to $0$ $\text{m}/\text{s}$.

To Find: the time interval of acceleration for  the bus.

Solution:

Initial speed of shuttle bus $\text{u}=9.8$ $\text{m}/\text{s}$

Final speed of shuttle bus $\text{v}=0$ $\text{m}/\text{s}$

acceleration $=3.8$ $\text{m}/\text{s}^2$

using first equation of motion

$\text{v}=\text{u}+\text{a}\text{t}$

as speed decreases acceleration will be negative

$\text{v}=\text{u}-\text{a}\text{t}$

putting value in equation

$0=9.8-3.8\text{t}$

$3.8\text{t}=9.8$

$\text{t}=\frac{9.8}{3.8}$

$\text{t}=2.58$ $\text{seconds}$

It takes $2.58\text{s}$ to decelerate to  $0$ $\text{m}/\text{s}$

Answer 2

The question is asking to calculate the time interval of acceleration for the bus and base on my own calculation, I would say that the answer would be 2.58 seconds. I hope you are satisfied with my answer and feel free to ask for more. I hope you are satisfied with my answer and feel free to ask for more