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algol [13]
3 years ago
15

Bertha has $2400 more invested at 4% than she has at 5%. If her annual income from these two investments is $294, how much does

she have invested at each rate?
Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0
So
x (4%)
y (5%)
x=y+2400
0.04x+0.05y=294

Once you solve them, x=4600 and y=2200
so 4%= $4600
5%= $2200
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Help on this please.
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Answer:

total - given, 360 -139 = 221

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2 years ago
What are the vertex and xintercepts of the graph of the function below?<br> y=(x + 4)(x-2)
erik [133]

Yo sup??

y=(x+4)(x-2)

to find the x intercept put y=0

0=(x+4)(x-2)

so either x=-4 or x=2

Therefore the graph intersects the x axis at -4 and 2

Lenght of x intercept=|-4-2|=6 units

y=(x+4)(x-2)

=x^2+2x-8

This is an upward opening parabola

To find the coordinates of the vertex we can apply the formula

(-b/2a,-D/4a)

b=2

a=1

D=b^2-4ac

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=4+32=36

Vertex=(-2/2*1,-36/4*1)

=(-1,-9)

Hope this helps.

3 0
3 years ago
One garden has 5 times more raspberry bushes than another garden. After 22 bushes were transplanted from the first garden to the
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One had 55. one had 11
4 0
3 years ago
Read 2 more answers
Ada makes sparkling juice by mixing 2 cups of sparkling water with every 4 cups of apple juice. Let s represent the number of cu
Dafna11 [192]

Answer:

s = 2j

Step-by-step explanation:

Given - Ada makes sparkling juice by mixing 2 cups of sparkling water

            with every 4 cups of apple juice. Let s represent the number of

            cups of sparkling water and j represent the number of cups of

             apple juice.

To find - Write an equation that shows how s and j are related.

Proof -

Let total number of cups of sparkling water make = s

     Total number of cups of apple juice make = j

Now,

Given that, Ada makes sparkling juice by mixing 2 cups of sparkling water with every 4 cups of apple juice.

⇒2s = 4j

⇒s = 2j

∴ we get

Ada can makes sparking water by mixing 2j cups of sparking water with every j cups of apple juice.

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3 years ago
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Informally assess the degree of visual overlap of two numerical data distributions with similar variabilities, measuring the difference between the centers by expressing it as a multiple of a measure of variability.


- Hope this helps!
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3 years ago
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