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antoniya [11.8K]
3 years ago
8

I'm an idiot. please help​

Mathematics
2 answers:
SOVA2 [1]3 years ago
7 0

Answer:

Third option is right

.................

sergejj [24]3 years ago
7 0

Answer:

What kind of math are you doing in middle school?

Step-by-step explanation:

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A scientist has started a bacteria culture with 1,000 cells. The cells will double every hour. 1. Write the sequence that repres
babymother [125]

Answer:

See below in bold.

Step-by-step explanation:

1.   The sequence is 1000, 2000, 4000, 8000.

2.  The common ratio  is 2000/1000 = 2.

3.   Number of bacteria after 7 hours is 1000(2)^(7- 1)

    = 64,000.

4.   1000(2)^(x-1)  > 1,000,000

2^x-1  > 1000

x- 1  log 2 > log 10

x- 1 > 9.96

x > 10.96

During the 11th hour.

8 0
3 years ago
A super clearance sale, bathing suits were marked 85% off. What is the sale price of a bathing suit that was originally priced $
liraira [26]
Answer: 9$
Explanation: 15% is how much a person will pay and 15% of 60 is 9$
5 0
3 years ago
Select the correct<br> function<br> that represents<br> this data.
lidiya [134]

Answer:

f(x) = -5x - 2

Step-by-step explanation:

Plug in the first set of values into each possible equation. Whichever equation yields the correct ouputs (y-values) for ALL input (x-values) is the correct answer. For the function f(x) = -5x - 2,  f(-2) = 8, f(-1) = 3 and so on... So f(x) = -5x - 2 is the correct answer!

Hope this helps!

5 0
2 years ago
if a rental car costs Caden $35 for the day, plus $0.33 per mile and his total bill was $78, how many miles did he drive?​
Digiron [165]
78-35= 43
43/.33= 130.30

130.3 miles
7 0
3 years ago
Find an equation in standard form for the hyperbola with vertices at (0, ±9) and foci at (0, ±11)
Katen [24]

Answer:

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 is standard equation of hyperbola with vertices at (0, ±9) and foci at (0, ±11).

Step-by-step explanation:

We have given the vertices at (0, ±9) and foci at (0, ±11).

Let (0,±a)  = (0,±9) and (0,±c)  = (0,±11)

The standard equation of parabola is:

\frac{y^{2} }{a^{2} } -\frac{x^{2} }{b^{2} }=1

From statement, a  = 9

c² = a²+b²

(11)²  = (9)²+b²

121-81  = b²

40  = b²

Putting the value of a² and b² in standard equation of parabola, we have

\frac{y^{2} }{81} -\frac{x^{2} }{40} }=1 which is the answer.

3 0
3 years ago
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