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antoniya [11.8K]
3 years ago
8

I'm an idiot. please help​

Mathematics
2 answers:
SOVA2 [1]3 years ago
7 0

Answer:

Third option is right

.................

sergejj [24]3 years ago
7 0

Answer:

What kind of math are you doing in middle school?

Step-by-step explanation:

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If f(x)=x2+x and g(x)=x-3, find f(g(7))​
babunello [35]

f(g(7)) = 20

Hope it helps you...

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How many solutions does the equation -3a + 3a + 6 = 7
STALIN [3.7K]
No solution because -3a +3a is cancelled out and 6 does not equal 7

3 0
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Using Parallel Lines Find m 1 and m 2. Explain your reasoning.
Molodets [167]

i don't know if there is a graph for this problem, but m1 should always equal m2

if m1 and m2 are parallel, one line that is perpendicular to m1 is always perpendicular to m2, and the slopes of m1 and m2 are equal and their lines should never intersect

8 0
4 years ago
benny uses 2/5 grams (G) of toothpaste each time he brushes his teeth. If benny buys 30-g tube, how many times will be able to b
worty [1.4K]

Answer:

75

Step-by-step explanation:

First divide 2/5 to get 0.4. Then divide 30 by 0.4 to get the answer. A simple way to think about it is how many 0.4 grams are in 30 gram tube.

5 0
3 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
4 years ago
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