Change each improper fraction to a mixed number. 10/4____?

Mathematics

1 answer:

AlexFokin [52]2 years ago

6 0

Answer:

2 2/4

Step-by-step explanation:you first see how many times the bottom number goes into the top number, then you put the remainder in a fraction!!

You might be interested in

A company is testing and comparing two candle designs. The box plots show the number of hours that each candle design lasts befo

Natalija [7]

Since these are box plots, they're based on a lot of data, and we cannot say for certain whether something will be true, but it can give us a good idea. So this means that options A & B are out, since they say 'will always', but we can never say for sure with box plots.

The boxes of the box plot represent basically the average of the data. The beginning of the box is the first quartile, the end of the box is the third quartile, and the line in the middle is the median, which is the middle of the data. Since the box in the box plot of Design A is greater than the box in the box plot of Design B, we can say it's likely that candle Design A will last longer than candle Design B, or option C.

3 0

3 years ago

Suppose the time to complete a 200-meter backstroke swim for female competitive swimmers is normally distributed with a mean μ =

hammer [34]

Answer:

The swimmer must complete the 200-meter backstroke in no more than 130 seconds.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 141, \sigma = 7$