Answer: 4(5j+7) = 20j+28
Step-by-step explanation:
japones ^^
look you have to multiply
8 cm x 6cm
20cm x 6 cm
and the answer that comes out of the multiplication is the correct one
Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19
Step-by-step explanation:
Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = birth weights of babies
µ = mean weight
σ = standard deviation
From the information given,
µ = 3500 grams
σ = 560 grams
We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as
P(x > 4000) = 1 - P(x ≤ 4000)
For x = 4000,
z = (4000 - 3500)/560 = 0.89
Looking at the normal distribution table, the probability corresponding to the z score is 0.81
P(x > 4000) = 1 - 0.81 = 0.19
The awnser is C because there is a right angle which is 90 degrees then there is also a vertical angle of 118 degrees. There is also a supplementary angle of 70 degrees. When you add these angles you get 278 degrees which you subtract from 360 to find the last angle which is K and you get 82 degrees
