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3 years ago

Order each number greatest to least 1/2, -2, square root of 5, -7/4, 2.4PLEASE HELP ME

Mathematics

1 answer:

Luden [163]3 years ago

4 0

Answer:

I think its

2.4, square root of 5, 1/2, -7/4, -2

hope this helps :D

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Regular hexagon ABCDEF is inscribed in circle X and has an apothem that is 6√3 inches long. Use the length of the apothem to cal

TEA [102]

Perimeter is 12*6 =72

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2 years ago

The value of 37 − − √ − 24 − − √ 37−24 is between:

Effectus [21]

Answer:23 And 24

Step-by-step explanation:

((37 - (−√(−24))) - (−√(37))) - 24 =

19.0827625 + 4.89897949 i

19.0827625

+ 4.89897949

23.98174199

23.98174199 is between 23 and 24

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2 years ago

Uninhibited growth can be modeled by exponential functions other than A(t) =Upper A 0 e Superscript kt. For example, if an i

laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than $A(t)=A_{0}e^{kt}$ . for example, if an initial population P₀ requires n units of time to triple, then the function $P(t)=P_{0}(3)^{\frac{t}{n} }$ models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form $P(t)=P_{0}(3)^{\frac{t}{n} }$ that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form $A(t)=A_{0}e^{kt}$ .

Answer: a) $P(t)=50(3)^{\frac{t}{30} }$

b) P(t) = 280 insects

c) t = 74 days

d) $A(t)=50e^{0.037t}$

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

$P(t)=50(3)^{\frac{t}{30} }$

b) In t = 47 days:

$P(t)=50(3)^{\frac{t}{30} }$

$P(47)=50(3)^{\frac{47}{30} }$

$P(47)=50(3)^{1.567}$

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

$750=50(3)^{\frac{t}{30} }$

$\frac{750}{50}=(3)^{\frac{t}{30} }$

$(3)^{\frac{t}{n} }=15$

Using the property Power Rule of logarithm:

$log(3)^{\frac{t}{30} }=log15$

$\frac{t}{30}log(3)=log15$

$t=\frac{log15}{log3} .30$

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

$A(t)=A_{0}e^{kt}$

$3A_{0}=A_{0}e^{30k}$

$3=e^{30k}$

Use Power Rule again:

$ln3=ln(e^{30k})$

$ln3=30k$

$k=\frac{ln3}{30}$

k = 0.037

Equation for exponential growth will be:

$A(t)=50e^{0.037t}$

3 0

2 years ago

kaleb was playing a video game it took him eight lives to beat the first world it took eight times as many to beat the second wo

KengaRu [80]

Bet its 64,no problem

4 0

3 years ago

Read 2 more answers

How to use this photo

siniylev [52]

First of all, your fractions that you wrote were wrong. You flipped the numbers over. When you're finding the slope of a graph, the number on the y-axis is always the numerator while the x-axis is the denominator.

Your first answer would be the actual slope- which is 3.

Your second answer would be the number of products that company would sell if the got 1,000 web views So just multiply 3 by 1,000. That means that the company will sell 3,000 products.

3 0

3 years ago