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lara [203]
3 years ago
7

Simplify 6.92 to the exponent of 1000

Mathematics
1 answer:
melisa1 [442]3 years ago
4 0

Answer:

Whatever is raised to the power of 0 is 1

SO the answer is 1

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Solve the equation, if possible.
Shalnov [3]

Answer:

no solution

Step-by-step explanation:

Given

- 3 | 6n - 2 | + 5 = 8 ( subtract 5 from both sides )

- 3 | 6n - 2 | = 3 ( divide both sides by - 3 )

| 6n - 2 | = - 1

The absolute value always returns a positive value and so

| 6n - 2 | ≠ - 1

Hence there is no solution to the equation

4 0
3 years ago
Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?
iren [92.7K]
Y=-7/2x+1/2
1. find slope
2. plug in slope to y=mx+b
3. take point and plug it in (find a b)
4. plug in slope and b to get equation
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3 years ago
Read 2 more answers
Factoring the expression 15x+6 using GCF
s344n2d4d5 [400]
The answer is 3(5x+2) i hope this helps you.
3 0
3 years ago
Fill in the blanks to complete the proof
-BARSIC- [3]

The blanks in this two-column proof should be filled as follows:

<u>Statements                                             Reasons</u>_______________

m∠1 = m∠3                                                Given

m∠CBA = m∠ABE + m∠CBD            Angle Addition Postulate  

m∠ABE = m∠3 + m∠2              Substitution Property of Equality          

m∠CBD = m∠3 + m∠2              Substitution Property of Equality

m∠ABE ≅ m∠CBD                    Transitive Property of Equality

<h3>What is the Angle Addition Postulate?</h3>

In Mathematics, the Angle Addition Postulate states that the measure of an angle formed by two (2) angles that are placed side by side to each other is equal to the sum of the measures of the two (2) angles.

This ultimately implies that, the Angle Addition Postulate can be used to determine the measurement of a missing angle in a geometric figure or it can be used for calculating an angle that is formed by two (2) or more angles such as m∠CBA = m∠ABE + m∠CBD.

Read more on Angle Addition Postulate here: brainly.com/question/24746945

#SPJ1

5 0
1 year ago
Find the complex zeros of x^3+27. write f in factored form
aliina [53]
x^3+27=0&#10;\\x^3+3^3=0&#10;\\(x+3)(x^2-3x+9)=0&#10;\\x^2-3x+9=0&#10;\\a=1,b=-3,c=9&#10;\\&#10;\\x_{1,2}= \frac{-b\pm \sqrt{b^2-4ac} }{2a} = \frac{-(-3)\pm \sqrt{(-3)^2-4\times1\times9} }{2\times1} =\frac{3\pm \sqrt{-27} }{2} =\frac{3\pm 3\sqrt{3}i }{2} &#10;\\&#10;\\(x+3)(x-\frac{3+ 3\sqrt{3}i }{2})(x-\frac{3- 3\sqrt{3}i }{2})=0&#10;&#10;
4 0
3 years ago
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