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Svetllana [295]
3 years ago
8

What is the greatest common factor of 3 and 6? VX o ooo

Mathematics
2 answers:
Elena L [17]3 years ago
4 0

Answer:

answer is 3

Step-by-step explanation:

The factors of 3 are: 1, 3

The factors of 6 are: 1, 2, 3, 6

Then the greatest common factor is 3.

kow [346]3 years ago
3 0

Answer:

The GFC of 3 and 6 is 3

Step-by-step explanation:

Hope this helps :))

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Ray Of Light [21]

Answer:

180                                                  

Step-by-step explanation:

3 0
3 years ago
Alex went to the grocery store and bought 5 avocados. He paid $10 and received $4.50 in change. How much did each avocado cost i
Delvig [45]

Answer:

$1.10

Step-by-step explanation:

We have been that Alex went to the grocery store and bought 5 avocados. He paid $10 and received $4.50 in change.

First of all, we will find amount paid for 5 avocados by subtracting $4.50 from $10.

\text{Amount paid for 5 avocados}=\$10-\$4.50

\text{Amount paid for 5 avocados}=\$5.50

Now, we will divide $5.50 by 5 to find cost of each avocado.

\text{Cost of each avocado}=\frac{\$5.50}{5}

\text{Cost of each avocado}=\$1.10

Therefore, the cost of each avocado is $1.10.

3 0
3 years ago
What is the slope of the line that passes through the points (0,6) and (4,-1)
wlad13 [49]
To find the slope between the points, you would go through this process
(-1-6)/(4-0)
And we get
(-7)/4
Aka
-(7/4) which is our slope
3 0
3 years ago
Choose one of the factors of 1331x3 − 8y3.
daser333 [38]
B is the answer hope this helps :)
7 0
3 years ago
Read 2 more answers
1. The table shows the probabilities of a response chocolate or vanilla when asking a child or adult. Use the formula for condit
Stels [109]
\begin{matrix}&\text{chocolate}&\text{vanilla}&\text{total}\\\text{children}&0.14&0.26&0.40\\\text{adults}&0.21&0.39&0.60\\\text{total}&0.35&0.65&1.00\end{matrix}

a. "Chocolate" and "Adults" (whatever those mean) will be independent as long as

P(\text{chocolate}\cap\text{adults})=P(\text{chocolate})\cdot P(\text{adults})

"Chocolate" has the marginal distribution given by the second column, with a total probability of P(\text{chocolate})=0.35. Similarly, "Adults" has the marginal distribution described by the third row, so that P(\text{adults})=0.60. Then

P(\text{chocolate})\cdot P(\text{adults})=0.35\cdot0.60=0.21

Meanwhile, the joint probability of "Chocolate" and "Adults" is given by the cell in the corresponding row/column, with P(\text{chocolate}\cap\text{adults})=0.21.

The probabilities match, so these events are indeed independent.

Parts (b) and (c) are checked similarly.

b. Yes;


P(\text{children})\cdot P(\text{chocolate})=0.40\cdot0.35=0.14
P(\text{children}\cap\text{chocolate})=0.14

c. Yes;

P(\text{vanilla})\cdot P(\text{children})=0.65\cdot0.40=0.26
P(\text{vanilla}\cap\text{children})=0.26
5 0
3 years ago
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