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Kazeer [188]
3 years ago
14

Answer please lot's of points.

Mathematics
2 answers:
Svetlanka [38]3 years ago
3 0

Answer:

t≈8.0927

Step-by-step explanation:

h(t) = -16t^2 + 128t +12

We want to find when h(t) is zero ( or when it hits the ground)

0 =  -16t^2 + 128t +12

Completing the square

Subtract 12 from each side

-12  =  -16t^2 + 128t

Divide each side by -16

-12/-16  =  -16/-16t^2 + 128/-16t

3/4 = t^2 -8t

Take the coefficient of t and divide it by 8

-8/2 = -4

Then square it

(-4) ^2 = 16

Add 16 to each side

16+3/4 = t^2 -8t+16

64/4 + 3/4= (t-4)^2

67/4 = (t-4)^2

Take the square root of each side

±sqrt(67/4) =sqrt( (t-4)^2)

±1/2sqrt(67) = (t-4)

Add 4 to each side

4 ±1/2sqrt(67) = t

The approximate values for t are

t≈-0.092676

t≈8.0927

The first is before the rocket is launched so the only valid answer is the second one

prisoha [69]3 years ago
3 0

Answer:

your correct answer is t

Step-by-step explanation:

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The Venn diagram above represents the students who were sick one day in January at a Chicago high school. 80 students had only a
mrs_skeptik [129]

Answer:

370

Step-by-step explanation:

The venn diagram corresponds to students who were sick in January at a Chicago high school.

Students who had only fever= n(A) = 80

Students who had only headache= n(B) = 90

Students who had only cough  = n(C) =60

Students who had both cough and fever = n(AC) = 10

n(AB) = 40:n(BC) = 30  n(ABC) = 20

Hence total students = 800

no of students who were absent due to other reasons = 100

REmaining students = 700

Students who were sick = sum of all =330

So no of students who were at school = 700-330 = 370

5 0
3 years ago
Find the GCF
Kaylis [27]
Greatest Common Factor. let's go over that. GCF of 6 and 12 would be 6 because 6 goes into 6, 1 times and 6 goes into 12, 2 times. . and it is the largest. so first you see if the lower number can go directly into the higher number. So 28a^2 b^2 c^2, is made of 14abc× 2abc. so you can say 14abc goes into 28a2b2c2, 2abc times. therefore 14abc is the largest factor.
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How many real solutions are there for f(x) = (x + 3)^2 – 8?
Molodets [167]
There are 2 solutions. the highest degree of a polynomial is 2
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Find the area of the shaded portion in the equilateral triangle with sides 6.
LUCKY_DIMON [66]
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Therefore all angles = 60°
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7 0
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Jim's backyard is a rectangle that is 15 5/6 yards long and 10 2/5 yards wide. Jim buys sods in pieces that are 1 1/3 yards long
Ne4ueva [31]

We are given

Jim's backyard:

Length is

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width is

W=10\frac{2}{5} =\frac{52}{5} yards

Since, this is rectangle

so, we can find area of rectangle

A=L*W

A=(\frac{95}{6})*(\frac{52}{5})

A=\frac{494}{3} yard^2

Area of one sod:

length is

l=1\frac{1}{3} =\frac{4}{3} yards

width is

w=1\frac{1}{3} =\frac{4}{3} yards

Since, it is rectangle in shape

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Area=l*w

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Number of pieces of sod = (area of Jim's backyard)/(area of one sod)

N=\frac{\frac{494}{3} }{\frac{16}{9} }

now, we can simplify it

N=\frac{741}{8} pieces need ..............Answer

7 0
3 years ago
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