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Kazeer [188]
3 years ago
14

Answer please lot's of points.

Mathematics
2 answers:
Svetlanka [38]3 years ago
3 0

Answer:

t≈8.0927

Step-by-step explanation:

h(t) = -16t^2 + 128t +12

We want to find when h(t) is zero ( or when it hits the ground)

0 =  -16t^2 + 128t +12

Completing the square

Subtract 12 from each side

-12  =  -16t^2 + 128t

Divide each side by -16

-12/-16  =  -16/-16t^2 + 128/-16t

3/4 = t^2 -8t

Take the coefficient of t and divide it by 8

-8/2 = -4

Then square it

(-4) ^2 = 16

Add 16 to each side

16+3/4 = t^2 -8t+16

64/4 + 3/4= (t-4)^2

67/4 = (t-4)^2

Take the square root of each side

±sqrt(67/4) =sqrt( (t-4)^2)

±1/2sqrt(67) = (t-4)

Add 4 to each side

4 ±1/2sqrt(67) = t

The approximate values for t are

t≈-0.092676

t≈8.0927

The first is before the rocket is launched so the only valid answer is the second one

prisoha [69]3 years ago
3 0

Answer:

your correct answer is t

Step-by-step explanation:

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tino4ka555 [31]
If Heather puts in 1.36% of her salary into a retirement account and she makes $63,000 in a year, this can be solved by 1.36% x 63000. First convert 1.36% into a decimal. To do this, divide by 100.

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Heather would put $856.8 in for the whole year. To find how much per month, divide by 12.

856.8/12=71.<span>4
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Heather would put $71 into a retirement account each month.
<em>
</em><em>Note: This was solved by multiply the percent and then dividing by 12 months. You could also do this by dividing by 12 months first and then multiplying the percent.</em>


6 0
3 years ago
A soccer ball kicked from the ground with an initial velocity of 32 ft/s is given by the function
Greeley [361]

Answer:

In words the answer is between t=0 and t=2.

In interval notation the answer is (0,2)

In inequality notation the answer is 0<t<2

Big note: You should make sure the function I use what you meant.

Step-by-step explanation:

I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.

So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.

0=-16t^2+32t

0=-16t(t-2)

So at t=0 and t=2

So the ball is in the air between t=0 and t=2

Interval notation (0,2)

Inequality notation 0<t<2

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Step-by-step explanation:

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