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Kazeer [188]
4 years ago
14

Answer please lot's of points.

Mathematics
2 answers:
Svetlanka [38]4 years ago
3 0

Answer:

t≈8.0927

Step-by-step explanation:

h(t) = -16t^2 + 128t +12

We want to find when h(t) is zero ( or when it hits the ground)

0 =  -16t^2 + 128t +12

Completing the square

Subtract 12 from each side

-12  =  -16t^2 + 128t

Divide each side by -16

-12/-16  =  -16/-16t^2 + 128/-16t

3/4 = t^2 -8t

Take the coefficient of t and divide it by 8

-8/2 = -4

Then square it

(-4) ^2 = 16

Add 16 to each side

16+3/4 = t^2 -8t+16

64/4 + 3/4= (t-4)^2

67/4 = (t-4)^2

Take the square root of each side

±sqrt(67/4) =sqrt( (t-4)^2)

±1/2sqrt(67) = (t-4)

Add 4 to each side

4 ±1/2sqrt(67) = t

The approximate values for t are

t≈-0.092676

t≈8.0927

The first is before the rocket is launched so the only valid answer is the second one

prisoha [69]4 years ago
3 0

Answer:

your correct answer is t

Step-by-step explanation:

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Answer:

Step-by-step explanation:

f(x)= 12x2+5 should be written as  f(x) = 12x^2 + 5; the " ^ " symbol signifies exponentiation and is mandatory.

Here's how we find the inverse function.

1.  Apply the horizontal line test.  if a horizontal line intersects the graph in more than one place, the function is not one-to-one and does not have an inverse for all x.  However, if we focus on only [0, infinity), this part of the graph does have an inverse, which we can find as follows:

2.  Replace 'f(x)' with 'y:  y = 12x^2 + 5

3.  Interchange x and y:  x = 12y^2 + 5

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4.  Solve for y:  12y^2 = x - 5;   y^2 = ------------

                                                                12

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7 0
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pantera1 [17]
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Question 4 (fill-in-the-blank worth 3 points) (03.01) the gcf of 12 and 28 is _____. numerical answers expected!
likoan [24]
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4 0
3 years ago
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Klio2033 [76]
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Vikki [24]

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Step-by-step explanation:

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64.4÷100=0.644

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