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3 years ago

Could you help please..

Mathematics

1 answer:

Nitella [24]3 years ago

4 0

Since she needs 3 1/2 for 5, and you need to find one batch, get 3 1/2 and divide it by 5. Change 3 1/2 to an improper fraction (7/2). Now use KCS (keep change switch) Keep the 7/2, change division to multiplication, and switch 5/1 to 1/5. (7/2)•(1/5)

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3 years ago

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during a sale a dress is marked down for a selling price of $90 to a sale price of $81 what is the percent markdown

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4 years ago

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A hotel offers a reward program based on the number of night stayed. The function f(x) represents the number of free nights earn

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Answer:

a. A customer earns 1 free night per 10 nights stayed.

Step-by-step explanation:

The missing function is:

f(x) = x/10

The missing options are:

a. A customer earns 1 free night per 10 nights stayed.

b. A customer starts with 1 free night and then earns another free night after every 10 nights stayed.

c.A customer earns x – 10 free nights for every 10 nights stayed.

d. A customer earns 10 free nights after x number of nights stayed.

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3 years ago

Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes

yaroslaw [1]

Answer:

$\frac{y^{2}}{25}-\frac{x^{2}}{3}=1$

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: $(0,-\sqrt{28}),(0,\sqrt{28})$

eje conjugado = $2\sqrt{3}$

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

$\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1$

de los focos podemos obtener que:

$c=\sqrt{28}$

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

$b=\sqrt{3}$

podemos utilizar la siguiente fórmula para obtener a:

$c^{2}-a^{2}=b^{2}$

si despejamos a en la ecuación obtenemos lo siguiente:

$a=\sqrt{c^{2}-b^{2}}$

ahora podemos sustituir los valores:

$a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}$

$a=\sqrt{28-3}$

$a=\sqrt{25}$

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

$\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1$

$\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1$

$\frac{y^{2}}{25}+\frac{x^{2}}{3}=1$

si graficamos la hipérbola, queda como en el documento adjunto.

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3 years ago