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cricket20 [7]
3 years ago
9

Write 14% as a fraction and as a decimal.

Mathematics
2 answers:
NikAS [45]3 years ago
5 0
The answer is D

Divide the percent by 100
14/100=0.14

Simplify the fraction
14/100 simplified=7/50
Andreyy893 years ago
3 0
D.)7/50 = 0.14

Explanation:
First move your decimal two to the left which gives us 0.14 ultimately eliminating A and B next just simplify 14/100 which gives us 7/50
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Lelechka [254]

Answer:

8\sqrt{2}

Step-by-step explanation:

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3 years ago
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A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra
VMariaS [17]

Answer:

0.4 = 40% probability that both marbles are blue.

0.0667 = 6.67% probability that both marbles are yellow.

53.33% probability of one blue and then one yellow

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that N = 6

4 blue, which means that k = 4

Sample of 2, which means that n = 2

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that N = 6

2 yellow, which means that k = 2

Sample of 2, which means that n = 2

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,6,2,2) = \frac{C_{2,2}*C_{4,0}}{C_{6,2}} = 0.0667

0.0667 = 6.67% probability that both marbles are yellow.

What is the probability of one blue and then one yellow?

Total is 100%.

Can be:

Both blue(40%)

Both yellow(6.67%)

One blue and one yellow(x%). So

40 + 6.67 + x = 100

x = 100 - 46.67

x = 53.33

53.33% probability of one blue and then one yellow.

If you are told that both selected marbles are the same color, what is the probability that both are blue?

Conditional probability.

Event A: Both same color

Event B: Both blue

Probability of both being same color:

Both blue(40%)

Both yellow(6.67%)

This means that P(A) = 0.4 + 0.0667 = 0.4667

Probability of both being the same color and blue:

40% probability that both are blue, which means that P(A \cap B) = 0.4

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.4667} = 0.8571

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

8 0
3 years ago
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Alenkinab [10]

Answer:

234

Step-by-step explanation:


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3 years ago
How do you solve 21÷1/3
nordsb [41]

Answer:

63

Step-by-step explanation:

<u>When dividing by a fraction, it is the same a multiplying that fraction but the reciprocal of it.</u>

21 / 1/3 is same as 21 * 3/1

63

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8 0
3 years ago
A sign company charges $28 per yard for each custom-made banner. Ms.Gill orders two banners that are each 178 yards long, and on
zhuklara [117]

Given,

A sign company charges $28 per yard for each custom-made banner.

Ms.Gill orders two banners that are each 178 yards long, and one banner that is 258 yards long.

To find,

Total money paid by Ms. Gill.

Solution,

Total length of 2 banners of 178 yards = 356 yards

Third banner is 258 yards long.

Total length of the banners = 356 + 258

= 614 yards

The cost of each banner = $28 per yards.

Total amount paid by Ms. Gill is :

= $28 × 614

= $17,192

Hence, she will pay $17,192 for all the three banners.

8 0
2 years ago
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