Answer: The wavelength of red light is 2 times longer than the wavelength of violet light.
Step-by-step explanation:
Let be "x" the number of times the wavelength of red ligth is longer than the wavelength of violet light.
Knowing that the wavelength (measured in meters) of red light is about
and the wavelength (measured in meters) of violet light is
, you have to:
Divide the wavelength of red light (measured in meters) by the wavelength of violet light (measured in meters).
Then:
![x=\frac{wavelength\ of\ red\ light}{wavelength\ of\ violet\ light}\\\\x=\frac{8*10^{-7}}{4*10^{-7}}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7Bwavelength%5C%20of%5C%20red%5C%20light%7D%7Bwavelength%5C%20of%5C%20violet%5C%20light%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B8%2A10%5E%7B-7%7D%7D%7B4%2A10%5E%7B-7%7D%7D)
Remember the Quotiend of powers property:
![\frac{b^m}{b^n}=b^{(m-n)}](https://tex.z-dn.net/?f=%5Cfrac%7Bb%5Em%7D%7Bb%5En%7D%3Db%5E%7B%28m-n%29%7D)
Then:
The wavelength of red light is 2 times longer than the wavelength of violet light.
I got you fam
2(x - 4) - 4x = 0
2x - 8 - 4x = 0
-2x - 8 = 0
-2x -8 + 8 = 0 + 8 (add 8 both sides)
(divide both sides by -2)
x = -4
Hope this helps
Answer:
Step-by-step explanation:
For i figure
Radius=9×10^3
Diameter=18×10^3
For j figure
Radius=1m
Diameter=2m
For k
Radius=17×10^-2
Diameter=34×10^-2
For l
Radius=25×10^-3
Diameter=50×10^-3
So this is a BIDMAS question so first you do what’s in the brackets so you have (1-9x1-4) and you have to do the multiplication first out of that to get (1-9-4) which is -12 so then you have overall 36 / -12 + 1 + 2 so you have to do the division first so do 36/-12 to get -3 and you have -3 + 1 + 2 which is 0 so your answer is 0.