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IRISSAK [1]
3 years ago
11

Solve for x. what is 1900=1300(1+.0625)^x?

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
7 0
First rearrange as:
\frac{1900}{1300}=1.0625^{x}
Taking logs of both sides, we get:
log\ \frac{1900}{1300}=x\ log1.0625
x=\frac{log\frac{1900}{1300}}{log\ 1.0625}=6.26
x = 6.26.
Neporo4naja [7]3 years ago
4 0
   1900 = 1300(1 + 0.0625)ˣ
   1900 = 1300(1.0625)ˣ
   1300           1300
      1⁶/₁₃ = (1.0625)ˣ
㏑(1⁶/₁₃) = ln((1.0625)ˣ)
㏑(1⁶/₁₃) = x㏑(1¹/₁₆)
 ln(1¹/₁₆)     ln(1¹/₁₆)
    6.26 ≈ x
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irakobra [83]

Answer:

x = 10, y = 20

Step-by-step explanation:

Because two sides of the rightmost triangle are congruent, the base angles would follow suit. This means 5x - 10 = 3x + 10. Simplifying this we get:

2x = 20

x = 10

Next, in the other triangle, we can say the same thing, the base angles would be congruent. From this we can say that the other base angle is 4y. Using the exterior angle theorem, we can say that the two angles with x terms add to 4y. This means 3x + 10 + 5x - 10 is 4y. We already know x is 10, so substituting that in we get:

80 = 4y

y = 20

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Given a triangle with vertices A , B and C list all possible correspondences of the triangle with itself.
Mademuasel [1]

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Step-by-step explanation:

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What is a ratio that is equivalent to 12:35?
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Read 2 more answers
For what values of b are the vectors \langle -46, b, 10 \rangle and \langle b, b^2, b \rangle orthogonal
Jet001 [13]

Answer:

b = 6 or b = -6 (non-zero vectors)

b = 0 (zero vector)

Step-by-step explanation:

Two vectors \vec{a}=\langle a_1,a_2,a_3\rangle and \vec{b}=\langle b_1,b_2,b_3\rangle are orthogonal if their dot product is equal to 0, or in other words

a_1\cdot b_1+a_2\cdot b_2+a_3\cdot b_3=0

In your case,

\vec{a}=\langle -46, b, 10\rangle\\ \\\vec{b}=\langle b,b^2,b\rangle

Hence, if vectors a and b are orthogonal, then

-46\cdot b+b\cdot b^2+10\cdot b=0\\ \\-46b+b^3+10b=0\\ \\b^3-36b=0\\ \\b(b^2-36)=0\\ \\b(b-6)(b+6)=0\\ \\b=0\text{ or }b=6\text{ or }b=-6

Note, then if b = 0, then \vec{b}=\langle 0,0,0\rangle and zero-vector is orthogonal to any other vectors.

Thus, b = 6 or b = -6.

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3 years ago
Determine whether the statement is true or false. Justify your answers.
marusya05 [52]

Answer:

The graph of y = f(-x) is a reflection of the graph of y = f(x) in the x-axis. ⇒ False

The graph of y = -f(x) is a reflection of the graph of y = f(x) in the y-axis. ⇒ False

Step-by-step explanation:

<em>Let us explain the reflection about the axes</em>

  • If a graph is reflected about the x-axis, then the y-coordinates of all points on it will opposite in sign

Ex: if a point (2, -3) is on the graph of f(x), and f(x) is reflected about the x-axis, then the point will change to (2, 3)

  • That means reflection about the x-axis change the sign of y
  • y = f(x) → reflection about x-axis → y = -f(x)

  • If a graph is reflected about the y-axis, then the x-coordinates of all points on it will opposite in sign

Ex: if a point (-2, -5) is on the graph of f(x), and f(x) is reflected about the y-axis, then the point will change to (2, -5)

  • That means reflection about the y-axis change the sign of x
  • y = f(x) → reflection about y-axis → y = f(-x)

<em>Now let us answer our question</em>

The graph of y = f(-x) is a reflection of the graph of y = f(x) in the x-axis.

It is False because reflection about x-axis change sign of y

The graph of y = -f(x) is a reflection of the graph of y = f(x) in the x-axis

The graph of y = -f(x) is a reflection of the graph of y = f(x) in the y-axis.

It is False because reflection about y-axis change sign of x

The graph of y = f(-x) is a reflection of the graph of y = f(x) in the y-axis

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