Question

Solve for x. what is 1900=1300(1+.0625)^x?

Answer 1

First rearrange as:
$\frac{1900}{1300}=1.0625^{x}$
Taking logs of both sides, we get:
$log\ \frac{1900}{1300}=x\ log1.0625$
$x=\frac{log\frac{1900}{1300}}{log\ 1.0625}=6.26$
x = 6.26.

Answer 2

   1900 = 1300(1 + 0.0625)ˣ
   1900 = 1300(1.0625)ˣ
   1300           1300
      1⁶/₁₃ = (1.0625)ˣ
㏑(1⁶/₁₃) = ln((1.0625)ˣ)
㏑(1⁶/₁₃) = x㏑(1¹/₁₆)
 ln(1¹/₁₆)     ln(1¹/₁₆)
    6.26 ≈ x