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IRISSAK [1]
3 years ago
11

Solve for x. what is 1900=1300(1+.0625)^x?

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
7 0
First rearrange as:
\frac{1900}{1300}=1.0625^{x}
Taking logs of both sides, we get:
log\ \frac{1900}{1300}=x\ log1.0625
x=\frac{log\frac{1900}{1300}}{log\ 1.0625}=6.26
x = 6.26.
Neporo4naja [7]3 years ago
4 0
   1900 = 1300(1 + 0.0625)ˣ
   1900 = 1300(1.0625)ˣ
   1300           1300
      1⁶/₁₃ = (1.0625)ˣ
㏑(1⁶/₁₃) = ln((1.0625)ˣ)
㏑(1⁶/₁₃) = x㏑(1¹/₁₆)
 ln(1¹/₁₆)     ln(1¹/₁₆)
    6.26 ≈ x
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