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3 years ago

Determine whether the statement is true or false. Justify your answers.

Mathematics

1 answer:

marusya05 [52]3 years ago

7 0

Answer:

The graph of y = f(-x) is a reflection of the graph of y = f(x) in the x-axis. ⇒ False

The graph of y = -f(x) is a reflection of the graph of y = f(x) in the y-axis. ⇒ False

Step-by-step explanation:

<em>Let us explain the reflection about the axes</em>

If a graph is reflected about the x-axis, then the y-coordinates of all points on it will opposite in sign

Ex: if a point (2, -3) is on the graph of f(x), and f(x) is reflected about the x-axis, then the point will change to (2, 3)

That means reflection about the x-axis change the sign of y

y = f(x) → reflection about x-axis → y = -f(x)

If a graph is reflected about the y-axis, then the x-coordinates of all points on it will opposite in sign

Ex: if a point (-2, -5) is on the graph of f(x), and f(x) is reflected about the y-axis, then the point will change to (2, -5)

That means reflection about the y-axis change the sign of x

y = f(x) → reflection about y-axis → y = f(-x)

<em>Now let us answer our question</em>

The graph of y = f(-x) is a reflection of the graph of y = f(x) in the x-axis.

It is False because reflection about x-axis change sign of y

The graph of y = -f(x) is a reflection of the graph of y = f(x) in the x-axis

The graph of y = -f(x) is a reflection of the graph of y = f(x) in the y-axis.

It is False because reflection about y-axis change sign of x

The graph of y = f(-x) is a reflection of the graph of y = f(x) in the y-axis

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What is the work for 309÷76,255

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.004052
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305.020
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3 years ago

A textbook store sold a combined total of 477 sociology and math textbooks in a week. The number of sociology textbois sold was

denpristay [2]

Answer:

The correct answer is 218 math textbooks and 259 sociology textbooks.

Step-by-step explanation:

To solve this problem, we can make a system of equations. Let the number of sociology textbooks sold be represented by the variable "s" and the number of math textbooks sold be represented by the variable "m". Using these variables, we can make two equations:

s + m = 477

m + 41 = s

There are many ways to solve this system of equations. One approach we can take is substituting the value for s given by the second equation into the first equation. This is modeled below.

s + m = 477

(m + 41) + m = 477

Combining like terms on the left side of the equation yields:

2m + 41 = 477

Subtracting 41 from both sides of the equation gives us:

2m = 436

Finally, dividing both sides of the equation by 2 gives us:

m = 218

To solve for the number of sociology textbooks, we can substitute into either of our original equations.

m + 41 = s

(218) + 41 = s

s = 259

Therefore, your answer is m = 218 and s = 259, or 218 math textbooks and 259 sociology textbooks were sold.

Hope this helps!

6 0

3 years ago

I need help I would really thank whoever answers this for me

Mars2501 [29]

To do these problems, you plug in the ‘n’ value given into the equation.

a. 6j - 3 : j = 4
6(4) - 3
24 - 3
21

b. 1/2b + 5 : b = 14
1/2(14) + 5
7 + 5
12

c. 8 + 4k : k = 3.5
8 + 4(3.5)
8 + 14
22

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3 years ago

Read 2 more answers

Mary, Kate, and Sara are playing a card game called Shoe Store. The game is played with 36 cards, which make pairs of shoes. Mar

bekas [8.4K]

The anwser is b 36 divided by 3 is 12

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4 years ago

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago