To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square.
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial.
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2.
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial.
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1.
They are both 1.
x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
or (x+1)^2.
Would it like.. not be C?? Im guessing its C (:
12 + 8 + 9 = 29
60 - 29= 31
Jorge owes his father $31
180-50=130
x-y=130
x+y=50
2x=180
x=90
90+y=50
y=50-90
y=-40
Answer:
D, 6 x 3 x 3
Step-by-step explanation:
One area of a square is 3 x 3 there are 6 squares so we multiply by 6 too.
