1/4 divided By 2 Show Your Work On How You Got The Answer

0.2 ✕ -0.5 ✕ ( -0.9- -0.7)

Luba_88 [7]

Answer:

0.02

Step-by-step explanation:

$0.2\times -0.5\times (-0.9 - -0.7)= \\\\0.2\times -0.5 \times (-0.2)= \\\\0.02$

Hope this helps!

4 0

3 years ago

Read 2 more answers

A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for

Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

$\implies h=\frac{1}{w^2}$

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

$= 2\times \frac{1}{w^2}(w+2w)$

$=\frac{6w}{w^2}$

$=\frac{6}{w}$

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

$C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}$

$=2w^2+4w^2+\frac{12}{w}$

$=6w^2+\frac{12}{w}$

Differentiating with respect to w,

$C'(w) = 12w -\frac{12}{w^2}$

Again differentiating with respect to w,

$C''(w) = 12 + \frac{24}{w^3}$

For maxima or minima,

C'(w) = 0

$\implies 12w -\frac{12}{w^2}=0$

$\implies 12w^3 - 12=0$

$w^3-1=0\implies w = 1$

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0

3 years ago

Please answer quickly!! read the picture. thank you!!

Debora [2.8K]

Evet hocam proje konularını da bir insan değilim ki bir şey var ya

6 0

2 years ago

Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?

Cloud [144]

Answer:

True; quadrants I & IV

Step-by-step explanation:

We know the relation between sine and cosine function which is given by

$\sin^2 \theta +\cos^2 \theta = 1$

Let us solve this equation for cosine function.

$\cos^2 \theta = 1-\sin^2 \theta$

Take square root both sides. When ever we take square root we need to write the solution in plus minus form

$\sqrt{\cos^2 \theta}=\pm\sqrt{1-\sin^2 \theta}$

$\cos \theta=\pm\sqrt{1-\sin^2 \theta}$

$\cos \theta=-\sqrt{1-\sin^2 \theta}, \sqrt{1-\sin^2 \theta}$

If Θ is in quadrants I and IV then the value will be positive and if Θ is in II and III quadrant then the value is negative.

Hence, if Θ is in quadrants I & IV, then we have

$\cos \theta=\sqrt{1-\sin^2 \theta}$

Thus, the correct option is: True; quadrants I & IV

6 0

3 years ago

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Devaughn's age is three times Sydney's age. The sum of their ages is 96. What is Sydney's age?

snow_tiger [21]

Answer:

24

Step-by-step explanation:

24x3=72

72+24+96

7 0

3 years ago

Read 2 more answers