Ken's distance is: d(t)=1.7t
Ken's shadow is:
(14-6)/d(t)=14/s
8/d(t)=14/s
s=14d(t)/8
s=1.75d(t) and using the value for d(t) we have:
s=1.75(1.7t)
s=2.975t and if you want it in terms of d, d=1.7t, t=d/1.7 so
s=2.975(d/1.7)
s=1.75d
Answer:
154.8
Step-by-step explanation:
20% is equal to 20/100= 0.20. So, 0.20 multiplied by 129 will give you 20% of 129 which is 25.8. If Alan ran 20% more then you add 25.8 to 129 which gives you an answer of 154.8.
Equation: 20/100= 0.2
0.2* 129= 25.8
25.8+129= 154.8
Alan ran 154.8 laps.
Answer:
i think its an isoceles
Step-by-step explanation:
Answer:
-76-43i
Step-by-step explanation:
First expand the multiplied terms
8-3i-(64+64i-24i+24)
8-3i-(64+40i+24)
Simplify
8-3i-64-40i-24
-76-43i
