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3 years ago

Moses and Marvin buys a package of 8 pens for 4.00.Moses wants 5 and Marvin wants 3 how much should each student pay?

Mathematics

1 answer:

Arturiano [62]3 years ago

8 0

Answer: Moses pays $2.50, and Marvin pays $1.50.

Step-by-step explanation: To solve this question, you have to find the unit rate.

8 pens for $4

4/8= 0.5/1

So, one pen is equal to 50¢.

Then, you just have to multiply how many pens each one buys by the price of one pen.

0.5*5=2.5

0.5*3=1.5

When you add them together, you come up with the amount the question have in the beginning.

2.5+1.5= 4

To conclude, Moses pays $2.50, and Marvin pays $1.50.

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Show how to solve the problem 378 x 6 using place value with regrouping. Explain how you knew when to regroup.

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Answer

2,268

Explanation

By grouping 378 can be written as,

378 = 300 + 70 + 8

6× 378 = 6 × (300 + 70 + 8)

= (6×300) + (6×70) + (6×8)

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2 years ago

What value of k makes the equation true? (5a^2 b^3)(6a^k b)=30a^6 b^4

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we are given

$(5a^2 b^3)(6a^k b)=30a^6 b^4$

Firstly, we will simplify left side

and then we can solve for k

Left side is

$(5a^2 b^3)(6a^k b)$

we can arrange like terms

$(5a^2 6a^k)(b^3 b)$

$(5\times 6 a^2a^k)(b^3 b)$

$(30 a^2a^k)(b^3 b^1)$

now, we can use property of exponent

$a^m \times a^n=a^{m+n}$

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now, we can equate it with right side

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$30a^{2+k}b^{4}=30a^6 b^4$

We can see that both sides have 30 , a and b

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$2+k=6$

now, we can solve for k

$2+k-2=6-2$

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