Answer:
2^5
Step-by-step explanation:
64 = 2*16 = 2*2*8 = 2*2*2*4 = 2*2*2*2*2 = 2^5
Answer:
Sorry, I can't type well.
Answer:
The fourth term of the expansion is -220 * x^9 * y^3
Step-by-step explanation:
Question:
Find the fourth term in (x-y)^12
Solution:
Notation: "n choose k", or combination of k objects from n objects,
C(n,k) = n! / ( k! (n-k)! )
For example, C(12,4) = 12! / (4! 8!) = 495
Using the binomial expansion formula
(a+b)^n
= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n
For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is
C(n,3)a^(n-3)b^3
=C(12,3) * x^(12-3) * (-y)^(3)
= 220*x^9*(-y)^3
= -220 * x^9 * y^3
Answer:
Step-by-step explanation:
32
Here, your equation is x + y = 6
In order to calculate coordinates, put x = 0,
0 + y = 6,
y = 6
Now, put y = 0, x + 0 = 6
x = 6
So, Your Coordinates would be: (0, 6) & (6, 0)
Hope this helps!