If the perimeter of the square is 4x then the domain of the function will be set of rational numbers and the domain of the function y=3x+8(3-x) is set of real numbers.
Given The perimeter of the square is f(x)=4x and the function is y=3x+8(3-x)
We will first solve the first part in which we have been given that the perimeter of the square is 4x and we have to find the domain of the function.
First option is set of rational numbers which is right for the function.
Second option is set of whole numbers which is not right as whole number involves 0 also and the side of the square is not equal to 0.
Third option is set of integers which is not right as integers involve negative number also and side of square cannot be negative.
Hence the domain is set of rational numbers.
Now we will solve the second part of the question
f(x)=3x+8(3-x)
we have not told about the range of the function so we can put any value in the function and most appropriate option will be set of real numbers as real number involve positive , negative and decimal values also.
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The answer is 438.6...
(528+1/5)-(89+3/5)=438.6
Answers:
- Exponential and increasing
- Exponential and decreasing
- Linear and decreasing
- Linear and increasing
- Exponential and increasing
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Explanation:
Problems 1, 2, and 5 are exponential functions of the form 
where b is the base of the exponent and 'a' is the starting term (when x=0).
If 0 < b < 1, then the exponential function decreases or decays. Perhaps a classic example would be to study how a certain element decays into something else. The exponential curve goes downhill when moving to the right.
If b > 1, then we have exponential growth or increase. Population models could be one example; though keep in mind that there is a carrying capacity at some point. The exponential curve goes uphill when moving to the right.
In problems 1 and 5, we have b = 2 and b = 1.1 respectively. We can see b > 1 leads to exponential growth. I recommend making either a graph or table of values to see what's going on.
Meanwhile, problem 2 has b = 0.8 to represent exponential decay of 20%. It loses 20% of its value each time x increases by 1.
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Problems 3 and 4 are linear functions of the form y = mx+b
m = slope
b = y intercept
This b value is not to be confused with the previously mentioned b value used with exponential functions. They're two different things. Unfortunately letters tend to get reused.
If m is positive, then the linear function is said to be increasing. The line goes uphill when moving to the right.
On the other hand if m is negative, then we go downhill while moving to the right. This line is decreasing.
Problem 3 has a negative slope, so it is decreasing. Problem 4 has a positive slope which is increasing.
To find the percentage of a number, first, convert it to a decimal and then multiply.
To convert a percentage to a decimal, move the decimal point over 2 spaces to the left. That makes 80% = 0.80
Then multiply 0.80 by 30.
0.80 • 30 = 24
Peggy got 24 questions correct.
Two ratios form a proportion if they are equal. If one fraction is equivalent to the other fraction, they form a proportion. To find out, reduce both fractions and see if they are equal.
A
1/2 and 4/2
Reduce 4/2 to 2/1.
1/2 and 2/1 are not equal.
1/2 and 4/2 do not form a proportion.
B
2/1 and 4/8
Reduce 4/8 to 1/2.
2/1 and 1/2 are not equal.
2/1 and 4/8 do not form a proportion
C
1/2 and 8/4
Reduce 8/4 to 2/1.
1/2 and 2/1 are not equal.
1/2 and 8/4 do not form a proportion
D
2/1 and 16/8
Reduce 16/8 to 2/1
2/1 and 2/1 are equal.
2/1 and 16/8 form a proportion.
Answer: D. 2/1 and 16/8
