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3 years ago

Help me with this!!!

Mathematics

1 answer:

gulaghasi [49]3 years ago

3 0

Answer: (3,3)

Midpoint formula = ( $\frac{x1+x2}{2}$ , $\frac{y1+y2}{2}$ )

6 + 0 / 2 = 2

1 + 5 / 2 = 7

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In February, Paul's electric bill was three dollars more then one-half his gas bill. If the electric bill was ninety-two dollars

USPshnik [31]

Answer:

49$

Step-by-step explanation:

7 0

3 years ago

I know the answer to number 7 but I just want to see if you guys know it

elixir [45]

Plugging 10 for k in the expression gives us
$2(10)^2+5(10)+1$ We simplify this expression to $200+50+1=251$
251 is your answer

4 0

3 years ago

Read 2 more answers

If r = 8 units and h = 10 units, what is the volume of the cylinder shown above? use 3.14 for pi,

Basile [38]

I hope this helps you

Volume =pi.r^2.h

Volume =3,14.8^2.10

Volume =31,4.64

Volume =200,96

8 0

3 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

3 years ago

4x + 3 = x + 2(x + 7) x=

stiv31 [10]

Answer:

X= -11/4 + -1/4 √145 or X= -11/4 + 1/4 √145

Step-by-step explanation:

Hope this helped<3

4 0

3 years ago