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3 years ago

6.8 . 10^4 standard form

1 answer:

6 0

The answer would be 68000 you can find it easily by moving the decimal to the right if the exponent is positive if its negative move it to the left.

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Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic

Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

b) $s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

c) For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

$SS = \sum_{i=1}^n (X_i -\bar X)^2$

And the sample variance for this case can be calculated from this formula:

$s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

8 0

2 years ago

Tan x-1/tan x+1=1-cot x/1+cotx

ikadub [295]

$\dfrac{\tan x-1}{\tan x+1}=\dfrac{\frac{\sin x}{\cos x}-1}{\frac{\sin x}{\cos x}+1}=\dfrac{\sin x-\cos x}{\sin x+\cos x}=\dfrac{1-\frac{\cos x}{\sin x}}{1+\frac{\cos x}{\sin x}}=\dfrac{1-\cot x}{1+\cot x}$

6 0

2 years ago

Noe take 5 minutes to rides his to down the hill to school and 10 minutes to rides up the hill from school Monday though Friday.

Sophie [7]

5x5=25 + 5x10=50

50+25=75

75x2=150 minutes

7 0

3 years ago

Rewrite the expression (4x^2+5x)^2-5 (4x^2+5x)-6 as a product of four linear factors.

tensa zangetsu [6.8K]

=16x4+40x3+5x2−25x−6

4 0

3 years ago

The sum of all prime factors of 100 is

Taya2010 [7]

Answer:

Step-by-step explanation:

prime factorization of 100

100 = 2 * 2 * 5 * 5

Sum of all prime factors

2 + 2 + 5 + 5 = 14

-------------------------

Extra credit

Sum of unique prime factors

2 + 5 = 7

8 0

2 years ago