Answer:
C would be your answer
Hope this helps!
Step-by-step explanation:
Given:
m∠B = 44°
Let's find the following measures:
m∠A, m∠BCD, m∠CDE
We have:
• m∠A:
Angle A and Angle B are interior angles on same side of a transversal.
The interior angles are supplementary.
Supplementary angles sum up to 180 degrees
Therefore, we have:
m∠A + m∠B = 180
m∠A + 44 = 180
Subtract 44 from both sides:
m∠A + 44 - 44 = 180 - 44
m∠A = 136°
• m,∠,BCD:
m∠BCD = m∠A
Thus, we have:
m∠BCD = 136°
• m∠CDE:
Angle C and angle CDE form a linear pair.
Linear pair of angles are supplementary and supplementary angle sum up to 180 degrees.
Thus, we have:
m∠D = m∠B
m∠D = 44°
m∠CDE + m∠D = 180
m∠CDE + 44 = 180
Subract 44 from both sides:
m∠CDE + 44 - 44 = 180 - 44
m∠CDE = 136°
ANSWER:
• m∠A = 136°
,
•
,
• m∠BCD = 136°
,
•
,
• m∠CDE = 136°
Answer: {(-5, 6), (-3, 13), (-14, 30)} is a function
{(12, 12), (12, 13), (12, 14)} and {(1, 3), (4, 5), (4, 9), (6, 19)} are not a function
Answer:
126 hrs
Step-by-step explanation:
-Given the school year has 180 days and the non-working student spends 42 minutes more than the working student.
-The total time during the school year is calculated as;
We convert our calculated time in hour(1hr=60 minutes):
Hence, the average non-working spends an average of 126 hrs that the working student.
