The possibility is 3/10 aka 3 over 10 i am very sure this is the answer but i might be wrong i have before
What types of problems can be solved using the greatest common factor? What types of problems can be solved using the least common multiple? Complete the explanation.
<span>*** Use the words 'same' and 'different' to complete the following sentences.*** </span>
<span>Problems in which two different amounts must be split into (the same) number of groups can be solved using the GCF. Problems with events that occur on (different) schedules can be solved using the LCM.</span>
100 minus 95 equals 5
25 equals 5%
100 divided by 5 equals 20
20 times 25 equals 500
500 minus 25 equals 475
Answer:475 students present/ 500 students total in school
Answer:
as we know Sara need 8 tube in 3 experiment
she will use 2 tube in 1 experiment
now she have 6 tube in other experiments
so the question said to find how many tube were used in both experiment equally so 3,3 test tube were needed for each of the other two experiment
Step-by-step explanation:
total tube=8 (3 experiment)
used =2tube (1 experiment)
remaining=8-2=6
now ,
dividing 6 into 2 equal part
so,=6/2=3
so 3 tube were used in 2nd experiment and 3in 3rd experiment
Answer:
23 females are right handed and 9 are left handed
Step-by-step explanation:
So to get this answer :
18 OF THE 41 RIGHT HANDED EMPLOYEES ARE MALE.
The statement means that there are 41 right handed employees and 18 of those are male thus the remaining are FEMALE.
To find the number of right handed employees who are female just subtracted 18 from 41 ( becaus etotal number of right handed males is 18 and the total number of right handed employees is 41.)
SO 23 FEMALES IN THE COMPANY ARE RIGHT HANDED.
Because 23 females are right handed that means to get the number of left handed females you subtract the total number of right handed females from the total number of females in the company THUS:
32 - 23 = 9 LEFT HANDED FEMALES
HOPE IT HELPED
