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2 years ago

9

Mathematics

1 answer:

stiks02 [169]2 years ago

8 0

Answer:QB = 1/2 QE

QC = CF

DE = 2AB

Step-by-step explanation: hope it works

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The DingGnat Doorknob Company intends to sell a new line of square doorknobs. The price-demand function is p ( x ) = 48.5 − 0.09

pickupchik [31]

Answer:

a. 135 doorknobs

b. $R(x) = 48.5x-0.09 x^2$

Step-by-step explanation:

The price-demand function is:

$p(x) = 48.5-0.09 x$

a. At a price of $36.30, the number of doorknobs sold, 'x' is:

$p(x) = 48.5-0.09 x\\36.30 = 48.5-0.09 x\\x= \frac{48.5-36.30}{0.09}\\x=135.55$

Rounding it down to the nearest whole unit, the company can sell 135 doorknobs at $36.30

b. Revenue is the product of the price, p(x), by the demand, x. Therefore, the Revenue function is:

$R(x) = x*p(x)=x(48.5-0.09 x)\\R(x) = 48.5x-0.09 x^2$

5 0

2 years ago

Find half of 6 times 8

Paladinen [302]

Answer:

Step-by-step explanation:

6 times 8 is 48 and i divided that by 2

5 0

3 years ago

Read 2 more answers

What is 364 x 26 distributive property

masha68 [24]

(300+64)x(20+6) just divide te numbers into diferrent groups

3 0

2 years ago

Brainliest question please help please help me now

pickupchik [31]

Answer:

51.53 units for th perimeter

Step-by-step explanation:

Use the Pythagorean theorem to find the diagonals then add everything together. Don't round until the very end for a closer answer

7 0

3 years ago

Help please and show the steps. thanks!

castortr0y [4]

${x}^{4} - 5 {x}^{3 } + 7 {x}^{2} - 5x + 6 = 0 \\ - 5x( {x}^{2} + 1) + ( {x}^{2} )^{2} + 7 {x}^{2} + 6 = 0 \\ {x}^{2} = u \\ - 5x( {u} + 1) + (u^{2} + 7 u + 6) =0$

$u^{2} + 7 u + 6=0 \\ u_1 = - 1 \\ u_2= - 6 \\ (u-u_1)(u-u_2) \\ u^{2} + 7 u + 6 = (u + 1)(u + 6)$

$- 5x( {u} + 1) + u^{2} + 7 u + 6 = 0 \\ - 5x(u + 1) + (u + 1)(u + 6) = 0 \\ u = {x}^{2} \\ - 5x( {x}^{2} + 1) + ( {x}^{2} + 1)( {x}^{2} + 6) =0$

$( {x}^{2} + 1)( {x}^{2} - 5x + 6) = 0$

Now we have 2 equations

${x}^{2} + 1 = 0 \\ {x}^{2} = - 1 \\ x_1 = i \\ x_2 = - i$

${x}^{2} - 5x + 6 = 0 \\ D = {( - 5)}^{2} - 4 \times 6 = 1 = {1}^{2} \\ x_3= \frac{5 + 1}{2} = 3 \\ x_4 = \frac{5 - 1}{2} = 2$

$Answer:x_1=-i, x_2=i, x_3=2, \\ x_4=3$

8 0

2 years ago