**Answer:**

575,010.25

**Explanation:**

i = 5%. n = 20 Years. P = 6,500,000.

Annual Maintenance Cost for the first five years, A1 = 25,000.

Annual Maintenance Cost from year 6 thro' 15, A2 = 30,000.

Annual Maintenance Cost from year 16 thro' 20, A3 = 35,000.

Overhaul Costs = 500,000 at year 10.

EUAC = [6,500,000 + 500,000 (P/F, 5%, 10)] (A/P, 5%, 20) +

25,000 +[{5000 (F/A, 5%, 5) + 5000(F/A, 5%, 15)} (A/F, 5%, 20)]

= [6,500,000 + 500,000 (0.6139)] (0.0802) +

25,000 +[{5000 (5.526) + 5000 (21.579)}(0.0302)]

= 545,917.39 + 29,092.86 = 575,010.25