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marshall27 [118]
3 years ago
9

Select all the correct equations.

Mathematics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

that's the answer

Step-by-step explanation:

#platolivesmatter

You might be interested in
Show with work please.
kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that \text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)

-\text{cos} \left(\theta\right)

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

\text{sec}(-\theta)=\text{sec}(\theta)

And, \text{sec}(\theta)=-0.73

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0
3 years ago
For the function defined by [Image Displayed], What is the constant of proportionality?
GaryK [48]

Answer:

I think the answer is undefined because the question above is an expression of f of x not a statement of variation which should have a constant of proportionality

3 0
3 years ago
What is 4(x-7)=2(x+3)?
hram777 [196]

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

4(x−7)=2(x+3)

Simplify both sides of the equation.

4(x−7)=2(x+3)

4x+−28=2x+6

4x−28=2x+6

Subtract 2x from both sides.

4x−28−2x=2x+6−2x

x−28=6

Add 28 to both sides.

2x−28+28=6+28

2x=34

Divide both sides by 2.

2x/2  =  34/2

x = 17

5 0
3 years ago
Read 2 more answers
When comparing the two sets of data, what is a true statement
PolarNik [594]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
28, 45, 12, 34, 36, 45, 19, 20
Alborosie

1) Mean of the set of data: 29.88

2) Mean absolute deviation: 10.13

3) See explanation

Step-by-step explanation:

1)

The mean of a set of data it is calculated as

\bar x = \frac{1}{N}\sum x_i

where

N is the number of data in the set

x_i is the value of each point in the  dataset

For the set of data in this problem, we have:

x_i =[28, 45, 12, 34, 36, 45, 19, 20]

And the number of values is

N = 8

Therefore, we can calculate the mean:

\bar x = \frac{1}{8}(28+ 45+ 12+ 34+ 36+ 45+ 19+ 20)=\frac{239}{8}=29.88

2)

The mean absolute deviation of a set of data is given by

\delta = \frac{1}{N}\sum |x_i-\bar x|

where

N is the number of values in the dataset

x_i are the single values

\bar x is the mean of the dataset

The dataset here is

x_i =[28, 45, 12, 34, 36, 45, 19, 20]

The mean, calculated in part 1), is

\bar x = 29.88

And

N = 8

Therefore the mean absolute deviation is

\delta = \frac{1}{8}(|28-29.88|+|45-29.88|+|12-29.88|+|34-29.88|+|36-29.88|+|45-29.88|+|19-29.88|+|20-29.88|)=\frac{81}{8}=10.13

3)

The mean of a dataset is the sum of the single values of the dataset divided by the number of values. The mean represents the value \bar x for which, if the dataset would have N values all equal to \bar x, the sum of the values of the dataset would be the same as the sum of the actual values.

The mean absolute deviation for a set of data represents the average of the absolute deviations of the single points from the mean of the dataset. This quantity gives a measure of the "dispersion" of the points around the mean: in fact, the larger the mean absolute deviation is, the more the points are "spread" around the mean of the dataset. Instead, if the mean absolute deviation is small, it means that the points are closer to the mean value.

Learn more about mean and spread of a distribution:

brainly.com/question/6073431

brainly.com/question/8799684

brainly.com/question/4625002

#LearnwithBrainly

7 0
4 years ago
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