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3 years ago

How do I solve this?

Mathematics

2 answers:

My name is Ann [436]3 years ago

7 0

Answer:

Step-by-step explanation:

x^2 + 2y^2

Let x=3 and y =2

3^2 + 2 ( 2)^2

Exponents first

9 + 2* 4

Then multiply

9+8

Then add

yulyashka [42]3 years ago

6 0

Answer:

Step-by-step explanation:

● x^2 + 2y^2

Replace x by 3 and y by 2

● (3)^2 + 2×(2)^2

● 9 + 2 × 4

● 9 + 8

● 17

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What is step 2 in the problem-solving process?

s344n2d4d5 [400]

Read the problem.
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Do the work.

6 0

3 years ago

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2/6 +36 Whats the answer ?

777dan777 [17]

36 2/6

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3 years ago

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Factor the expression:

Dovator [93]

Answer:

B) (4x-5i)(4x+5i)

Step-by-step explanation:

The expression can be treated as the difference of squares, and factored accordingly. That factoring is ...

a² -b² = (a -b)(a +b)

Here, we have ...

a² -b² = 16x² -(-25)

a² = 16x² ⇒ a = 4x

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6 0

3 years ago

If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.

galina1969 [7]

Answer:

$\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h}$ is your average rate of change,

Step-by-step explanation:

average rate of change is

$\frac{f(a+h)-f(a)}{a+h-a}$ , by slope formula

simplify this to get $\frac{f(a+h)-f(a)}{h}$ , which is the definition of the derivative as h goes to 0

$\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}$

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

$\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}$

simplifying

$\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h}$ (your average rate of change)

6 0

3 years ago

3(4a + 2) = 2(a - 2)?

Likurg_2 [28]

Answer:

A= -1

Step-by-step explanation:

8 0

3 years ago

How do I solve this?​

How do I solve this?