Question

The median of the marks 10, 13, 3x-1, 3x+1, 18, 18 arranged in ascending order is

Answer 1

Answer:

a. Marks = 10, 13, 14, 16, 18, 18

b. mode = 18

c. Range = 8

Step-by-step explanation:

==>Given the following data set arranged in ascending order:

10, 13, 3x-1, 3x+1, 18, 18

Median = 15

==>Required:

a. Marks:

To get each marks, let's find the value of x since we know median to be 15.

10, 13, [3x-1, 3x+1], 18, 18

Our median in this even number of data set would be the average of the 2 middle values which would give us 15.

Thus, we have:

[(3x-1) + (3x+1)] ÷ 2 = 15

[3x-1 + 3x+1] ÷ 2 = 15

[3x+3x-1+1] ÷ 2 = 15

6x/2 = 15

Multiply 2 by both sides

6x = 30

Divide 6 by both sides

x = 5

Now let's plug in the value of x to get out marks:

10, 13, 3(5)-1, 3(5)+1, 18, 18

10, 13, 14, 16, 18, 18

b. Mode is the most appeared data value, which is 18

c. Range is the difference between the highest and lowest value = 18 - 10 = 8