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2 years ago

The median of the marks 10, 13, 3x-1, 3x+1, 18, 18 arranged in ascending order is

Mathematics

1 answer:

Lorico [155]2 years ago

5 0

Answer:

a. Marks = 10, 13, 14, 16, 18, 18

b. mode = 18

c. Range = 8

Step-by-step explanation:

==>Given the following data set arranged in ascending order:

10, 13, 3x-1, 3x+1, 18, 18

Median = 15

==>Required:

a. Marks:

To get each marks, let's find the value of x since we know median to be 15.

10, 13, [3x-1, 3x+1], 18, 18

Our median in this even number of data set would be the average of the 2 middle values which would give us 15.

Thus, we have:

[(3x-1) + (3x+1)] ÷ 2 = 15

[3x-1 + 3x+1] ÷ 2 = 15

[3x+3x-1+1] ÷ 2 = 15

6x/2 = 15

Multiply 2 by both sides

6x = 30

Divide 6 by both sides

x = 5

Now let's plug in the value of x to get out marks:

10, 13, 3(5)-1, 3(5)+1, 18, 18

10, 13, 14, 16, 18, 18

b. Mode is the most appeared data value, which is 18

c. Range is the difference between the highest and lowest value = 18 - 10 = 8

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A bakery recorded the number of muffins and bagels it sold for a seven day period. For the data presented, what does the value o

atroni [7]

Answer:

Mean of bagel

Step-by-step explanation:

Working out each of the statically summaries Given in the option :

Mean of muffin :

Mean = Σx / n

n = sample size

(61 + 20 + 32 + 58 + 62 + 61 + 56) / 7

= 350 / 7

= 50

Mean of bagel :

Mean = Σx / n

n = sample size

(34 + 45 + 43 + 42 + 46 + 72 + 75) / 7

= 357 / 7

= 51

Hence, from the result obtained, we could see that the value of 51 summarizes the mean of bagel.

3 0

2 years ago

Eggs are sold in boxes. A small box holds 6 eggs.A large box holds 12 eggs.Hina buys x small boxes of eggs.Hina also buys 4 less

yuradex [85]

Answer:

a) 12x - 48 or 6(2x - 8)

b) 18x - 48 or 6(3x - 8)

Step-by-step explanation:

A small box holds 6 eggs

A large box holds 12 eggs.

Hina buys x small box of eggs

Hina also buys (x-4) large box of eggs

a) Total number of eggs in the large box by Hina = (x-4)12

= 12x - 48

= 6(2x - 8)

b) Total number of eggs bought by Hina = (x) 6 + (x-4)12

= 6x + 12x - 48

= 18x - 48

= 6(3x - 8)

8 0

3 years ago

Help please..................

JulsSmile [24]

The answer is 120 lol

4 0

2 years ago

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago

Which two values are solutions to the inequality r ≤ 5?

sergij07 [2.7K]

Answer:

Step-by-step explanation:The solution is x > 3

7 0

3 years ago