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vovangra [49]
3 years ago
8

The equation shows the relationship between x and y:

Mathematics
1 answer:
Masja [62]3 years ago
5 0
I believe the answer is -5
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4.11.1 Practice: Assignment. Please help i will mark brainliest! ​
amm1812

Step-by-step explanation:

x2 + 7x + 12

x2 + 4x + 3x + 12

x(x + 4) + 3( x + 4)

(x + 3) and (x + 4) are the factors

4x2 + 6x + 2

4x2 + 4x + 2x + 2

4x (x + 1) + 2(x + 1)

(x + 1) and (4x + 2) are the factors

5 0
3 years ago
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Complete the table for the given rule
irinina [24]

Answer:

see explanation :)

Step-by-step explanation:

y = − x − 4

is in the slope-intercept form for a linear equation,  

y = m x + b , where  m  is the slope and  b  is the y-intercept. In the given equation,  

m = − 1  and  b = − 4 .


Ordered Pairs

x ... ... . . y

4 ... . − 8

2 ... . − 6

0 ... . − 4

− 2 . ...− 2

− 4 ... . . 0

7 0
3 years ago
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Solve the second equation.<br>2x - y = 8<br>First, solve for (-y).<br>--y =<br>​
kicyunya [14]

Answer:

-y=-2x+8\\y=2x-8

Step-by-step explanation:

To solve, first subtract 2x from both sides.

2x-y=8\\-y=-2x+8

You appear to want the solution for -y, so I've included it. Given that you also want the solution for y, divide both sides by -1.

-y=-2x+8\\y=2x-8

5 0
3 years ago
Solve the Following expression d=5 2d+4d-9-7=
makkiz [27]

Answer:

14

Step-by-step explanation:

d=5 so

2(5)+4(5)-9-7

10+20-9-7

30-9-7

21-7

14

7 0
3 years ago
Read 3 more answers
How do you solve this type of problem, what would be the procedure? Assume PQRS is a parallelogram, if PQ=x2−10 and SR=3x , find
NeTakaya

Answer:

<em />x = 5<em />

<em />

Step-by-step explanation:

Given

Shape: Parallelogram PQRS

PQ = x^2 - 10

SR = 3x

Required

Find all possible values of x

<em>Every parallelogram have parallel and equal opposite sides;</em>

From the given parameters, one can easily deduce that PQ and SR are opposite sides;

This implies that

PQ = SR

Substitute values of PQ and SR

x^2 - 10 = 3x

Subtract 3x from both sides

x^2 - 10 -3x = 3x - 3x

x^2 - 10 -3x = 0

Rearrange

x^2  -3x- 10 = 0

Now, we have a quadratic equation;

Expand the above expression

x^2  +2x-5x- 10 = 0

Factorize

x(x+2)-5(x+2) = 0

(x-5)(x+2) = 0

x - 5 = 0   or    x + 2 = 0

Solve for x in both cases

<em />x = 5<em> or </em>x = -2<em />

<em />

<em>But x can't be negative;</em>

<em>So, the possible value of x is </em>

<em />x = 5<em />

6 0
3 years ago
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