2x - y = 5 3x + 2y = 4 Solve the system of equations. A) (3, 1) B) (0, 2) C) (2, -1) D) ( 9 7 , 17 7 )
1 answer:
Solve the system with elimination
multiply the first equation by two to cancel
2(2x-y=5) new equation 4x-2y=10
now the -2y and 2y cancel each other out
now you have 4x=10 + 3x=4 = 7x=14
divide by 7 to get x=2 now we have to find y by plugging x into one of the equations(let's use the first one)
2(2)-y=5 --> 4-y=5 --> -y =1 --> y =-1
(x,y) (2,-1)
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