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Dvinal [7]
3 years ago
9

YOU RRR MEH HEROOOZZ! PUHLEASZEEE ITS 10:30pm!!

Mathematics
1 answer:
avanturin [10]3 years ago
8 0

Answer:

x(35)\approx 11.8

Step-by-step explanation:

<u>Modeling With Functions </u>

We have a table of values of speeds vs distance taken for a car to stop. We are required to find a model that uses the square root and fits the given data to predict other values of d as a function of v.

By the nature of the problem, we can know that for v=0, d must be 0 too. So our model won't include a vertical shift or independent term. Being v the speed of the car and x the distance it takes to stop, we use the following model

x(v)=A\sqrt{v}

We must find A to make the function fit the data. Let's use the first point (v,x); (20,9)

9=A\sqrt{20}

Solving for A

\displaystyle A=\frac{9}{\sqrt{20}}

A\approx 2

Then we have

x(v)=2\sqrt{v}

Evaluating for v=35

x(35)=2\sqrt{35}=11.83

\boxed{x(35)\approx 11.8}

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Let u=x^2-4 and v=4x-5. By the product rule,

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}

By the power rule, we have (u^5)'=5u^4 and (v^4)'=4v^3, but u,v are functions of x, so we also need to apply the chain rule:

\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}

\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}

and we have

\dfrac{\mathrm du}{\mathrm dx}=2x

\dfrac{\mathrm dv}{\mathrm dx}=4

So we end up with

\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3

Replace u,v to get everything in terms of x:

\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3

We can simplify this by factoring:

10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)

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Answer:

The equation that represents Karla's sentence is 4y = y + 15

Step-by-step explanation:

From the question,

Four times a number is equal to the number increased by 15. To write the equation that represents the sentence, we will have to use a variable to represent the unknown number.

Since we are asked to use y for the variable, that is, let the number be y

Then

The statement, "four times a number" will be

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The number increased by 15 means y + 15.

Hence, the equation becomes

4y = y + 15

This is the equation that represent Karla's sentence.

If desired,

The unknown number can be determined by solving for y in the equation

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Step-by-step explanation:

1 = 16

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16 x 11 = 176

3 0
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