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mariarad [96]
2 years ago
9

How many unit cubes are in one layer?

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
3 0

Answer:

6 unit cubes

<u>Skills needed: Dimensioning</u>

Step-by-step explanation:

1) Layers are the length x width

The height determines the number of layers. There are 5 layers in this figure as the height is 5.

2) The length x width = 3 x 2  = 6

6 is the answer in this case.

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What is the value of x in the equation 1/2x - 2/3 y = 30, when y = 15
hammer [34]

Answer:

Step-by-step explanation:

1/2x - 2/3 × 15 = 30

1/2x - 10 = 30

1/2x = 30 + 10

1/2x = 40

x = 40 × 2

x = 80

hope this helps

plz mark it bas brainliest!!!!!!!!!

6 0
4 years ago
Read 2 more answers
Q1a) What fraction, decimal and percentage of the diagram is shaded?<br> 3 points<br> Your answer
Hitman42 [59]

Answer:

in this diagram their are boxes.

on which 21 are shaded so the fraction is

Step-by-step explanation:

21/100

because their are total 100 boxes and 21 are shaded

hope you like the answer.

5 0
3 years ago
Please help! The volume of an inflated spherical water balloon is 121,500 pi millimeters to the third. What is the radius of the
irga5000 [103]

Answer:

The radius of the inflated spherical balloon  is 45 millimeters.

Step-by-step explanation:

Volume of the spherical water balloon = 121,500 pi  cubic millimeters

Let the radius of the balloon = r

Now, Volume of a Sphere = \frac{4}{3} \pi r^{3}

⇒\frac{4}{3} \pi r^{3}  = 121,500 \pi

On solving for the value of r, we get:

r^{3}  = \frac{121,500\times 3}{4}   = 91125\\ \implies  r  = \sqrt[3]{91125}

or, r  = 45 millimeter

Hence, the radius of the inflated spherical balloon  is 45 millimeters.

5 0
4 years ago
The least common multiple of 3, 4, 6, and 8 is <br><br> A. 24.<br> B. 96.<br> C. 72.<br> D. 8.
garri49 [273]
Try the lowest option first. 8 is not divisible by 3 so you can rule out D. The next lowest option is 24. 24 is divisible by all 4 numbers so that it is the answer.

ANSWER: A) 24
6 0
3 years ago
Write the expression (4x-2)•6(2x+ 7) in the ax2+bx+c What are the values of the coefficient
tresset_1 [31]
The values of the coefficient are ax^2+bx+c=

48x^2-24x+84 and A= 48, B=-24, C=84.

(4x-2)•6(2x+7)=

6•2x+ 6•7

(4x-2)(12x+42)=

4x•12x= 48x^2 4x•42= 168.

-2•12x= -24x -2•42=-84

48x^2-24x+168-84=

48x^2-24x+84=

A= 48, B=-24, C=84

ax^2+bx+c= 48x^2-24x+84.
3 0
3 years ago
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