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3 years ago

Z + 21/–1 = –3. z+21/-1 is a fraction

Mathematics

2 answers:

Stella [2.4K]3 years ago

6 0

Answer:

1 Move the negative sign to the left.

z-21=-3

2 Add 21 to both sides.

z=-3+21z=−3+21

3 Simplify -3+21 to 18

z=18

Step-by-step explanation:

hope it helps

Vika [28.1K]3 years ago

3 0

Answer:

No Answer

Step-by-step explanation:

$z+\frac{21}{-1} =-3*z+\frac{21}{-1}$

cancel out same on both sides

$0=-3$

N/A

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a recipe calls for 24 fluid ounces of light whipping cream. if anthony has 1.5 pints of whipping cream in his refrigerator does

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Step-by-step explanation:

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3 years ago

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Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

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Furkat [3]

Answer:

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