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2 years ago

Z + 21/–1 = –3. z+21/-1 is a fraction

Mathematics

2 answers:

Stella [2.4K]2 years ago

6 0

Answer:

1 Move the negative sign to the left.

z-21=-3

2 Add 21 to both sides.

z=-3+21z=−3+21

3 Simplify -3+21 to 18

z=18

Step-by-step explanation:

hope it helps

Vika [28.1K]2 years ago

3 0

Answer:

No Answer

Step-by-step explanation:

$z+\frac{21}{-1} =-3*z+\frac{21}{-1}$

cancel out same on both sides

$0=-3$

N/A

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Find the value of x in the triangle shown below.<br> please help me

vaieri [72.5K]

Answer:

Final Answer: 59

Step-by-step explanation:

180- 62= 118

118 / 2= 59

so both angles would be 59

8 0

2 years ago

If the degree of a term is a fraction,the term is still a monomial

Mademuasel [1]

False,Monomials only have one term.Example: 6xy<span> . . . . . .A+

</span>

8 0

2 years ago

PLEASE HELP ME:<br><br> Find the perimeter of the figure. Round to the nearest tenth.

Ksenya-84 [330]

Answer:

perimeter = 20.9 units

Step-by-step explanation:

perimeter

perimeter = distance around two dimensional shape

= addition of all sides lengths

<h2>perimeter of the figure</h2><h2>= AB+BC+CD+AD</h2>

distance formula:

$d = \sqrt{( x_{2} - x_{1}) {}^{2} + ( y_{2} - y_{1}) {}^{2} }$

<h3>1) distance of AB</h3>

A(-3,0) B(2,4)

x1 = -3 x2 = 2

y1 = 0 y2 = 4

(substitute the values into the distance formula)

$ab = \sqrt{(2 - ( - 3)) {}^{2} + (4 - 0) {}^{2} }$

$ab = \sqrt{5 {}^{2} + 4 {}^{2} }$

$ab = \sqrt{41}$ AB = 6.4 units

<h3>2) distance of BC</h3>

B(2,4) C(3,1)

x1 = 2 x2 = 3

y1 = 4 y2 = 1

$bc = \sqrt{(3 - 2) {}^{2} + (1 - 4) {}^{2} }$

$bc = \sqrt{1 {}^{2} + ( - 3) {}^{2} }$

$bc = \sqrt{10}$

BC = 3.2 units

<h3>3) distance of CD</h3>

C(3,1) D(-4,-3)

x1 = 3 x2 = -4

y1 = 1 y2 = -3

$cd = \sqrt{( - 4 - 3) {}^{2} + ( - 3 - 1)) {}^{2} }$

$cd = \sqrt{( - 7) {}^{2} + ( - 4 ){}^{2} }$

$cd = \sqrt{65}$

CD = 8.1 units

<h3>4) distance of AD</h3>

A(-3,0) D(-4,-3)

x1 = -3 x2 = -4

y1 = 0 y2 = -3

$ad = \sqrt{( - 4 - ( - 3)) {}^{2} + ( - 3 - 0) {}^{2} }$

$ad = \sqrt{( - 1) {}^{2} + ( - 3) {}^{2} }$

$ad = \sqrt{10}$

AD = 3.2 units

<h2>perimeter of figure</h2>

= AB+BC+CD+AD

= 6.4 + 3.2 + 8.1 + 3.2

= 20.9 units

8 0

2 years ago

Given an initial quantity Q0=150 and a growth rate of 7% per unit time, give a formula for the quantity Q as a function of time

rodikova [14]

Answer:

Step-by-step explanation:

From the given information:

(a)

Since growth quantity is not continuous

$Q(t) = 150 (1.07)^t$

For t = 10

$Q(10) = 150 (1.07)^{10}$

$\mathbf{Q(10) = 295.073}$

(b)

Here, for a continuous growth rate, the growth quantity can be computed in terms of initial quantity and the growth rate.

i.e.

$Q(t) = 150 e^{0.07t}$

At t = 10 for a continuous growth rate;

$Q(10) = 150 e^{0.07 \times 10}$

$Q(10) = 150 e^{0.7}$

$\mathbf{Q(10) = 302.063}$

8 0

2 years ago

Which represents a quadratic function?

irinina [24]

Answer:

Option 2 is the correct answer

Step-by-step explanation:

A quadratic function is a function in which the highest power to which the variable is raised is 2

1) f(x) = −8x3 − 16x2 − 4x

The given function is a cubic function because the highest power

to which the variable,x is raised is 3

2) f(x) = 3x²/4 + 2x - 5

The given function is a quadratic function because the highest power

to which the variable,x is raised is 2

3) f(x) = 4/x² - 2/x + 1

It can be rewritten as

f(x) = 4x^-2 - 2x^-1 + 1

The given function is not a quadratic function because the highest power to which the variable,x is raised is - 2

4) f(x) = 0x2 − 9x + 7

It can be rewritten as

f(x) = - 9x + 7

The given function is not a quadratic function because the highest power to which the variable,x is raised is 1

3 0

2 years ago

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