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erastovalidia [21]
3 years ago
14

What are the indicated measures

Mathematics
2 answers:
const2013 [10]3 years ago
7 0
4n + 5n + 6 + 8n -12 + 9n +2 = 360 degrees

26n -4 = 360
26n = 364
<span> <span> <span> n = 14 degrees

</span></span></span>
<span> <span> <span> Angle A = 56
</span> <span> AngleD = 76 </span> <span>
Angle C = 100 </span> <span>
Angle B = 128 </span>
TOTAL =    360
</span></span>
marissa [1.9K]3 years ago
4 0
1. Solve for N
Add all terms together and set equal to 360
(4n)+(9n+2)+(8n-12)+(5n+6)=360
26N= 364
N= 14
M<A = 4(14)= 56
2.9(14)+2=128
3. 8(14)-12= 100
4. 76
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Anybody know the answers? A-? B-4 c-12 1/3?
shutvik [7]

Answer:

11.666666-repeated on and on

Step-by-step explanation:

but you can probably round to 11.7

7 0
3 years ago
The speed of light is about 3x10 to the 8th power meters per second. About how far can light travel in 30 minutes?
ella [17]
5.4x10^11 metres per second or 540,000,000,000 metres per second
7 0
3 years ago
A box with a square base and open top must have a volume of 32,000 cm3. find the dimensions of the box that mini- mize the amoun
zmey [24]
Alrighty


squaer base so length=width, nice


v=lwh
but in this case, l=w, so replace l with w
V=w²h

and volume is 32000
32000=w²h


the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW

alrighty

we gots
SA=W²+4HW and
32000=W²H

we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute

SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W

take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?

0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W

so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H

the box is 20cm height and the width and length are 40cm
7 0
3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

4 0
3 years ago
Read 2 more answers
Please help if you can!
Dima020 [189]

Answer:

m' (-2, 4)

n' (-2, 1)

o' (3, 1)

p' (3, 4)

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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