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Zina [86]
3 years ago
6

What's the answer??????????

Mathematics
2 answers:
pantera1 [17]3 years ago
6 0

Answer:

32

Step-by-step explanation:

2 +  {4}^{2}  \div 2 \times 5 - 10 \\ 2 + 16  \div 2 \times 5 - 10 \\ 2 + 8 \times 5 - 10 \\ 2 + 40 - 10 \\ 42 - 10 \\  = 32

hope this helps

brainliest appreciated

good luck! have a nice day!

IRISSAK [1]3 years ago
3 0

Answer:

32

Step-by-step explanation:

first simplify the exponent

4^2 = 16

so u would get

2 + 16 / 2 • 5 - 10

then divide and multiply to get

2 + 8 • 5 - 10

2 + 40 - 10

then add and subtract

42 - 10 = 32

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It's a lot like solving equations.

3b-7 < 32
Add 7 to each side.
3b < 39
Divide by 3 on each side.
b < 13

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you just subtract -4 by 6 and get -10

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On a blueprint, the scale says that 2 cm represents 3 m. What is the actual length of a wall if it's measurement on the blueprin
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3 years ago
3. In an auditorium, 1/6 of the students are fifth graders, 1/3 are fourth graders, and 1/4 of the remaining students are second
Katen [24]

12

<h3>Further explanation</h3>

<u>Given:</u>

In an auditorium,

  • \frac{1}{6} of the students are fifth graders,
  • \frac{1}{3} are fourth graders, and
  • \frac{1}{4} of the remaining students are second graders.

There are 96 students in the auditorium.

<u>Question:</u>

How many second graders are there?

<u>The Process:</u>

The least common multiple (LCM) of 3 and 6 is 6.

Let us draw the diagram of all students.

96 \div 6 \ units = 16 \rightarrow \boxed{16}\boxed{16}\boxed{16}\boxed{16}\boxed{16}\boxed{16} = 96 \ students

  • \frac{1}{6} of the students are fifth graders, or 1 of 6 units above, that is \boxed{16} = 16 \ students
  • \frac{1}{3} = \frac{2}{6} are fourth graders, or 2 of 6 units above, that is \boxed{16}\boxed{16} = 32 \ students

The remainder is 6 units - (1 unit + 2 units) = 3 units, that is \boxed{16}\boxed{16}\boxed{16} = 48 \ students. Or, 96 - 16 - 32 = 48 students.

\frac{1}{4} of the remaining students are second graders.

Let us count how many second graders are there.

\boxed{ \ \frac{1}{4} \times 48 \ students = ? \ }

Thus, there are 12 second-graders in the auditorium.

- - - - - - - - - -

Quick Steps

\boxed{ \ \frac{1}{4} \times \bigg(1 - \frac{1}{6} - \frac{1}{3} \bigg) \times 96 = ? \ }

\boxed{ \ = \frac{1}{4} \times \bigg(\frac{6}{6} - \frac{1}{6} - \frac{2}{6} \bigg) \times 96 \ }

\boxed{ \ = \frac{1}{4} \times \frac{3}{6} \times 96 \ }

\boxed{ \ = \frac{3}{24} \times 96 \ }

We crossed out 24 and 96.

\boxed{ \ = 3 \times 4 \ }

\boxed{\boxed{ \ = 12 \ students \ }}

<h3>Learn more</h3>
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Keywords: In an auditorium, 1/6 of the students, fifth graders, 1/3, fourth, 1/4, the remaining students, second, 96, how many, second graders

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Answer:

Domain: input values, independent variables

Range: output vales, dependent variables

Step-by-step explanation:

Think of it like a graph: the domain are the x-values and the range is the y-values. if you're doing a problem with time, the time will go on the x-axis and cannot be influenced by the y-values, but the y-vales are depending on what the x-values are (independent/dependent). for the input/output, usually when solving equations on a graph, you plug in the x-value and find the y-value. you're INPUTTING the x-value to receive the OUPUT.

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