Answer:
2y-3x+15 = 0
Step-by-step explanation:
let the equation of the perpendicular line: y=mx+c.
Given equation : 2x+3y=12
=> y=-2/3 x+4
so the sope of the equation is m1= -2/3.
as the two lines are mutually perpendicular,
so, m1*m2=-1
=> (-2/3)*m2= -1
=> m2= 3/2
the paerpendicular line : y=(3/2) x+c.
this line pass through (7,3)
so, 3 = (3/2)*7+c
=> c = -15/2
so the perpendicular line y = (3/2)*x -15/2
=> 2y-3x+15 = 0
Answer:
Step-by-step explanation:
-48
-72
-84
basically if its divisible by 12 its divisible by 3
Answer:
A
Step-by-step explanation:
Decimal place can be counted before multiplying. The multiply number without decimals, when you get the answer add the decimal place back.
Set up a system of equations.
0.10d + 0.25q = 39.25
d + q = 250
Where 'd' represents the number of dimes, and 'q' represents the number of quarters.
d + q = 250
Subtract 'q' to both sides:
d = -q + 250
Plug in '-q + 250' for 'd' in the 1st equation:
0.10(-q + 250) + 0.25q = 39.25
Distribute 0.10:
-0.10q + 25 + 0.25q = 39.25
Combine like terms:
0.15q + 25 = 39.25
Subtract 25 to both sides:
0.15q = 14.25
Divide 0.15 to both sides:
q = 95
Now plug this into any of the two equations to find 'd':
d + q = 250
d + 95 = 250
Subtract 95 to both sides:
d = 155
So there are 95 quarters and 155 dimes.
