3 years ago

Value of 3x^2 +4y^2 if x=2, y=1, and z= -3

1 answer:

4 0

$3x^2+4y^2\\\\\text{Put the values of x=2, y=1 and z=-3 to the expression:}\\\\3(2^2)+4(1^2)=3(4)+4(1)=12+4=16$

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