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maxonik [38]
3 years ago
5

Solve x squared add 5x add 6 =0

Mathematics
1 answer:
White raven [17]3 years ago
4 0

Answer:

x = -3 and x = -2

Step-by-step explanation:

<u>Step 1:  Convert words into an expression</u>

x squared add 5x add 6 =0

x^2 + 5x + 6 = 0

<u>Step 2:  Factor and Solve</u>

x^2 + 5x + 6 = 0

(x + 3)(x + 2) = 0

x + 3 - 3 = 0 - 3 and x + 2 - 2 = 0 - 2

x = -3 and x = -2

Answer:  x = -3 and x = -2

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What is (f+g)(x)?
Viktor [21]
(f+g)(x)=x^2-36+x^3+2x^2-10

(f+g)(x)=x^3+3x^2-46
6 0
3 years ago
Read 2 more answers
Find the approximate area of the regions bounded by the curves y = x/(√x2+ 1) and y = x^4−x. (You may use the points of intersec
Finger [1]

The approximate area of the region bounded by the curves f(x) = x / √(x² + 1) and g(x) = x⁴ - x is approximately 0.806.

<h3>How to determine the approximate area of the regions bounded by the curves</h3>

In this problem we must use definite integrals to determine the area of the region bounded by the curves. Based on all the information given by the graph attached below, the area can be defined in accordance with this formula:

A = A₁ + A₂                                                                (1)

A₁ = ∫ [g(x) - f(x)] dx, for x ∈ [- 0.786, 0]                   (2)

A₂ = ∫ [f(x) - g(x)] dx, for x ∈ [0, 1.151]                       (3)

g(x) = x⁴ - x                                                               (4)

f(x) = x / √(x² + 1)                                                      (5)

Then, we proceed to find the integrals:

∫ g(x) dx = ∫ x⁴ dx - ∫ x dx = (1 / 5) · x⁵ - (1 / 2) · x²                          (6)

∫ f(x) dx = ∫ [x / √(x² + 1)] dx = (1 / 2) ∫ [2 · x / √(x² + 1)] dx = (1 / 2) ∫ [du / √u] = √u = √(x² + 1)                                                                                  (7)

And the complete expression for the integral is:

A = A₁ + A₂                                                                                      (1b)

A₁ = (1 / 5) · x⁵ - (1 / 2) · x² - √(x² + 1), for x ∈ [- 0.786, 0]               (2b)

A₂ = √(x² + 1) - (1 / 5) · x⁵ + (1 / 2) · x², for x ∈ [0, 1.151]                  (3b)

A₁ = 0.023

A₂ = 0.783

A = 0.023 + 0.783

A = 0.806

The approximate area of the region bounded by the curves f(x) = x / √(x² + 1) and g(x) = x⁴ - x is approximately 0.806.

To learn more on definite integral: brainly.com/question/14279102

#SPJ1

6 0
2 years ago
Help pls im strugglin
loris [4]

66 is the correct answer

8 0
4 years ago
Given: △KLM, LM=20 3 <br> m∠K=105°, m∠M=30°<br> Find: KL and KM
hjlf

Okay, so the angle of K is 45° (180 - 135).

Draw a line that goes straight down from angle L and let's say that point is point Z. You can see that this triangle can be separated into two special triangles: the 45 45 90 triangle on the left (ΔLKZ) and the 30 60 90 triangle (ΔLMZ) on the right.

I don't know if you've learned this yet (just google them if you're confused):                                                                       - for a 45 45 90 triangle the sides are x, x, and x√2.                                                 - for a 30 60 90 triangle the sides are x, 2x, and x√3.

Since we know that LM is 20√3, using the 30 60 90 trick, you can see that LZ is 10√3 and MZ is 30.

Next, since LZ is 10 sqrt(3), using the 45 45 90 trick, <em>KL is 10√6</em> and KZ is 10 sqrt(3). Therefore, KM = KZ + MZ = <em>10√3 + 30</em>

<u>The answer: KL is 10√6, KM is 10√3 + 30</u>

(I'm sorry it's such a long explanation, pictures would have been better)

6 0
3 years ago
the model represents the factorization of 2x2+5x+3. what are the factors of the polynomial.(2x+3)(x+1),(2x-3)(x-1),(3x+2)(x-1),(
Maurinko [17]

Answer:

The factors of the polynomial are (2x + 3)(x + 1) ⇒ 1st answer

Step-by-step explanation:

* Lets explain how to factor a trinomial in the form ax² ± bx ± c  

- Look at the c term first.  

# If the c term is a positive number, then its factors r , s will both  

  be positive or both be negative it depends on the sign of b, if b  

  positive then both are positive if b negative then both are negative  

# a has two factors h and k  

# The brackets are (hx ± r)(kx ± s) where a = hk , c = rs and b = rk + hs  

# If the c term is a negative number, then either r or s will be negative,  

  but not both.  

# a has two factors h and k  

# The brackets are (hx + r)(kx - s) where a = hk , c = rs and b = rk - hs  

* Lets solve the problem

∵ The trinomial is 2x² + 5x + 3

∴ a = 2 , b = 5 , c = 3

∵ c is positive

∴ Its factors r and s have same sign

∵ b is positive

∴ r and s both positive

∵ a = 2  

∵ The factors of a are h , k

∵ 2 = 2 × 1

∴ h = 2 and k = 1

∵ c = 3

∵ The factors of c are r , s

∵ 3 = 3 × 1

∴ r = 3 and s = 1

∵ The brackets are (hx + r)(kx + s)

∴ 2x² + 5x + = (2x + 3)(x + 1)

* The factors of the polynomial are (2x + 3)(x + 1)

7 0
3 years ago
Read 2 more answers
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