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jeka94
2 years ago
14

An electrician needs to cut a 49 m piece of wire into two pieces so that one piece is 5 m longer than the other piece. What is t

he length of the shorter piece of wire? Enter your answer as a number only (no letters or symbols). Do not include units.
Mathematics
1 answer:
gulaghasi [49]2 years ago
3 0

The length of the shorter wire that the electrician cuts so that the difference between those two is of 5 m is 22.5.

Given to us

An electrician needs to cut a 49 m piece of wire into two pieces so that one piece is 5 m longer than the other piece.

<h3>What are the two equal parts of the wire?</h3>

We know that the length of the wire is 49 m, therefore, to cut the wire in two equal parts divide the total length of the wire by two,

\dfrac{49}{2} = 24.5

Thus, the length of each side will be 24.5.

<h3>What is the length of the shorter piece of wire?</h3>

Since we need to cut the wire such that one side of the wire is 5 less than the other, we already know the length of the equal sides deduct (5/2) from both sides to create a difference between the length of the wire.

Length of the shorter wire = 24.5 -2.5 = 22.5

Length of the longer wire = 22.5 + 5 = 27.5

Hence, the length of the shorter wire that the electrician cuts so that the difference between those two is of 5 m is 22.5.

Learn more about Lengths:

brainly.com/question/8552546

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Murljashka [212]

Answer:

93 times as many

Step-by-step explanation:

To figure this out, simply divide 837 by 9.

837/9=93

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A box holds 30 tins How many boxes can be filled<br> with 810 tins
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27 (810/30)?..............
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3 years ago
The scores of an eighth-grade math test have a normal distribution with a mean Mu = 83 and a standard deviation Sigma = 5. If Di
tresset_1 [31]

The missing choices are:

A. z-score = 92 - 83

B. z-score = (92 - 83)/5

C. z-score = 83 - 92

D. z-score =  (92 - 83)/92

The expression she would write to find z-score is z-score = \frac{92-83}{5} ⇒ B

Step-by-step explanation:

The rule of z-score is z = (x -μ)/σ, where

  • x is the score
  • μ is the mean
  • σ is the standard deviation

The scores of an eighth-grade math test have a normal distribution

∵ The mean is 83

∴ μ = 83

∵ The standard deviation is 5

∴ σ = 5

∵ Din’s test score was 92

∴ x = 92

- Substitute all of these values in the formula of z-score

∴ z-score = \frac{92-83}{5}

The expression she would write to find z-score is z-score = \frac{92-83}{5}

Learn more:

You can learn more about z-score in brainly.com/question/7207785

#LearnwithBrainly

5 0
3 years ago
Let ABC be a triangle such that AB=13 BC=14 and CA=15. D is a point on BC such that AD Bisects
Yuri [45]

Answer:

Area of triangle ADC  is 54 square unit

Step-by-step explanation:

Here is the complete question:

Let ABC be a triangle such that AB=13, BC=14, and CA=15. D is a point on BC such that AD bisects angle A. Find the area of triangle ADC .

Step-by-step explanation:

Please see the attachment below for an illustrative diagram

Considering the diagram,

BC = BD + DC = 14

Let BD be x ; hence, DC will be 14-x

and AD be y

To, find the area of triangle ADC

Area of triangle ADC  = \frac{1}{2} (DC)(AD)

= \frac{1}{2}(14-x)(y)

We will have to determine x and y

First we will find the area of triangle ABC

The area of triangle ABC can be determined using the Heron's formula.

Given a triangle with a,b, and c

Area =\sqrt{s(s-a)(s-b)(s-c)}

Where s = \frac{a+b+c}{2}

For the given triangle ABC

Let a = AB, b = BC, and c = CA

Hence, a = 13, b= 14, and c = 15

∴ s = \frac{13+14+15}{2} \\s= \frac{42}{2}\\s = 21

Then,

Area of triangle ABC = \sqrt{(21)(21-13)(21-14)(21-15)}

Area of triangle ABC = \sqrt{(21)(8)(7)(6)} = \sqrt{7056}

Area of triangle ABC = 84 square unit

Now, considering the diagram

Area of triangle ABC = Area of triangle ADB + Area of triangle ADC

Area of triangle ADB = \frac{1}{2} (BD)(AD)

Area of triangle ADB = \frac{1}{2}(x)(y)

Hence,

Area of triangle ABC =  \frac{1}{2}(x)(y) + \frac{1}{2}(14-x)(y)

84 =   \frac{1}{2}(x)(y) + \frac{1}{2}(14-x)(y)

∴ 84 = \frac{1}{2}(xy) + 7y - \frac{1}{2}(xy)

84 = 7y\\y = \frac{84}{7}

∴ y = 12

Hence, y = AD = 12

Now, we can find BD

Considering triangle ADB,

From Pythagorean theorem,

/AB/² = /AD/² + /BD/²

∴13² = 12² + /BD/²

/BD/² = 169 - 144

/BD/ = \sqrt{25}

/BD/ = 5

But, BD + DC = 14

Then, DC = 14 - BD = 14 - 5

BD = 9

Now, we can find the area of triangle ADC

Area of triangle ADC  = \frac{1}{2} (DC)(AD)

Area of triangle ADC  = \frac{1}{2} (9)(12)

Area of triangle ADC  = 9 × 6

Area of triangle ADC  = 54 square unit

Hence, Area of triangle ADC  is 54 square unit.

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3 years ago
What does x equal in -6(8+7x)=-342?
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It equals 20 because if you work it out that would be the answer
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4 years ago
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