An electrician needs to cut a 49 m piece of wire into two pieces so that one piece is 5 m longer than the other piece. What is t
1 answer:
The length of the shorter wire that the electrician cuts so that the difference between those two is of 5 m is 22.5.
Given to us
An electrician needs to cut a 49 m piece of wire into two pieces so that one piece is 5 m longer than the other piece.
<h3>What are the two equal parts of the wire?</h3>We know that the length of the wire is 49 m, therefore, to cut the wire in two equal parts divide the total length of the wire by two,
Thus, the length of each side will be 24.5.
<h3>What is the length of the shorter piece of wire?</h3>Since we need to cut the wire such that one side of the wire is 5 less than the other, we already know the length of the equal sides deduct (5/2) from both sides to create a difference between the length of the wire.
Length of the shorter wire = 24.5 -2.5 = 22.5
Length of the longer wire = 22.5 + 5 = 27.5
Hence, the length of the shorter wire that the electrician cuts so that the difference between those two is of 5 m is 22.5.
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Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
