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kicyunya [14]
3 years ago
11

Find the product. 4x - 3y(-2x 2y)

Mathematics
2 answers:
liubo4ka [24]3 years ago
4 0
(4x + 3y)² = 

<span>(4x)² + 2 (4x) (3y) + (3y)² = </span>

<span>16x² + 24xy + 9y²</span>
zavuch27 [327]3 years ago
3 0
Hello,
The product of <span>4x - 3y(-2x 2y) is:
 6x^2y^2+4x
Thank you (:</span>
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Ok for this one im really stuck and i need help.just want to make sure i understand this one.
tangare [24]

Answer:

70 - 5√10 ft²

Explanation:

Perimeter is the distance around a two-dimensional shape.

                       area of rectangle: length x width

Here given:

length: (3√2 + 4√5) ft

width: (-5√2 + 5√5) ft

Solve for perimeter:

length x width

(3√2 + 4√5) x (-5√2 + 5√5)

<u>apply distributive method</u>

(3√2)(-5√2) + (3√2)(5√5) + (4√5)(-5√2) + (4√5)(5√5)

<u>multiply</u>

-15(2) + 15√10 -20√10 + 20(5)

<u>combine</u>

-30 -5√10 + 100

<u>simplify</u>

70 - 5√10

4 0
2 years ago
a student named sarah hill follow the steps below to find her magic number 1 find the number of letters in her first name 2 find
Nata [24]
Her magic number is 126.
4 0
3 years ago
Read 2 more answers
Please Help! Question is:
Natasha_Volkova [10]

Answer: D

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please someone help me!!
ozzi

Answer:

5 feet squared

Step-by-step explanation:

7 0
3 years ago
The thicknesses of 81 randomly selected aluminum sheets were found to have a variance of 3.23. Construct the 98% confidence inte
Yuliya22 [10]

Answer:

The confidence interval for the population variance of the thicknesses of all aluminum sheets in this factory is Lower limit = 2.30, Upper limit = 4.83.

Step-by-step explanation:

The confidence interval for population variance is given as below:

[(n - 1)\times S^{2}  /  X^{2}  \alpha/2, n-1 ] < \alpha < [(n- 1)\times S^{2}  / X^{2} 1- \alpha/2, n- 1 ]

We are given

Confidence level = 98%

Sample size = n = 81

Degrees of freedom = n – 1 = 80

Sample Variance = S^2 = 3.23

X^{2}_{[\alpha/2, n - 1]}   = 112.3288\\\X^{2} _{1 -\alpha/2,n- 1} = 53.5401

(By using chi-square table)

[(n – 1)*S^2 / X^2 α/2, n– 1 ] < σ^2 < [(n – 1)*S^2 / X^2 1 -α/2, n– 1 ]

[(81 – 1)* 3.23 / 112.3288] < σ^2 < [(81 – 1)* 3.23/ 53.5401]

2.3004 < σ^2 < 4.8263

Lower limit = 2.30

Upper limit = 4.83.

8 0
2 years ago
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