Answer:
1701 and 2667 and 376 and 5472
Step-by-step explanation:
Answer:
2 (4x - 1) + 6 = 8x + 4 = 4(2x+1)
Step-by-step explanation:
2 (4x - 1) + 6
= (2*4x + 2*-1) + 6
= 8x - 2 + 6
= 8x + 4
= 4/(2x+1)
Answer:
B. (1,5) and (5.25, 3.94)
Step-by-step explanation:
The answer is where the 2 equations intersect.
We need to solve the following system of equations:
y = -x^2 + 6x
4y = 21 - x
From the second equation:
x = 21 - 4y
Plug this into the first equation:
y = -(21 - 4y)^2 + 6(21 - 4y)
y = -(441 - 168y + 16y^2)+ 126 - 24y
y = -441 + 168y - 16y^2 + 126 - 24y
16y^2 + y - 168y + 24y + 441 - 126 = 0
16y^2 - 143y + 315 = 0
y = [-(-143) +/- sqrt ((-143)^2 - 4 * 16 * 315)]/ (2*16)
y = 5, 3.938
When y = 5:
x = 21 - 4(5) = 1
When y = 3.938
x = 21 - 4(3.938) = 5.25.
The solution to the above factorization problem is given as f′(x)=4x³−3x²−10x−1. See steps below.
<h3>What are the steps to the above answer?</h3>
Step 1 - Take the derivative of both sides
f′(x)=d/dx(x^4−x^3−5x^2−x−6)
Step 2 - Use differentiation rule d/dx(f(x)±g(x))=d/dx(f(x))±d/dx(g(x))
f′(x)=d/dx(x4)−d/dx(x^3)−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−d/dx(x3)−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x2−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x^2−10x−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x^2−10x−1−dxd(6)
f′(x)=4x^3−3x^2−10x−1−0
Learn more about factorization:
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Answer:
-2, -6
Step-by-step explanation:
using cramer rule
5 -3
-2 -1
calculatiing the determinant = (5 x-1) - (-3x-2) = -5 -(6) = -5-6=-11
using cramer rule
to calculate x we change the coefficient of x with the answer (8,10)
8 -3
10 -1
we calculate determinant = (8x-1)-(-3x10) = -8-(-30) = -8+30 =22
to calculate x
22/-11= -2
to calculate y we change the coefficient of y with the answer (8,10)
5 8
-2 10
we calculate determinant = (5x10)-(8x-2) = 50 -(-16) = 50 +16=66
to calculate y
66/-11= -6
