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Maurinko [17]
3 years ago
11

Can someone help me urgently

Mathematics
1 answer:
cluponka [151]3 years ago
8 0

Answer:

which answer did you need help with

Step-by-step explanation:

i dont see what your inquiring about

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Delia worked 45 minutes on her oil painting.She took a break at 10:35 a.m.At what time did Delia start working on her painting
rjkz [21]
Um i think it would be 9:55

4 0
3 years ago
Read 2 more answers
Taylor ran 2 1/4 miles and walked 2 4/5 miles. How far did she run and walk
irinina [24]
Okay. So, we should convert fractions to the least common denominator, which is 20. That would be 2 5/20 and 2 16/20. Add both of those numbers up to get 5 1/20. Taylor ran and walked 5 1/20 miles.
5 0
3 years ago
Write 2 fractions equivalent to 7/12
NeTakaya

Answer:

14/24 And 21/36

Step-by-step explanation:

Just multiply the fractions by any number. In this case 2 and 3.

4 0
2 years ago
A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

4 0
3 years ago
-2(2x- _)+1=17-4x For what missing value is the equation an identity?
igor_vitrenko [27]
What’s grade are you?
4 0
2 years ago
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